You apply the same amount of heat to 5 grams of water and 5 grams of aluminum. The temperature of the aluminum increases more th
1 answer:
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Answer:
Rms speed of the particle will be
Explanation:
We have given mass of the air particle
Gas constant R = 8.314 J/mol-K
Temperature is given T =
We have to find the root mean square speed of the particle
Which is given by
So rms speed of the particle will be
Answer:
The magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.
Explanation:
Given;
distance half way between the parallel wires, r = ¹/₂ (40 cm) = 20 cm = 0.2 m
current carried in opposite direction, I₁ and I₂ = 10 A and 20 A respectively
The magnitude of the magnetic field halfway between the wires can be calculated as;
where;
B is magnitude of the magnetic field halfway between the wires
I₁ is current in the first wire
I₂ is current the second wire
μ₀ is permeability of free space
r is distance half way between the wires
Therefore, the magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.
Answer:
d = 1.047 mm
Explanation:
given,
diameter of the wire = 2.0-cm
length of solenoid = 15 cm = 0.15
Current in the wire = I = 2.5 A
magnetic field = B = 3.0 mT
Magnetic field inside the solenoid
N x d = l
d = 1.047 x 10⁻³ m
d = 1.047 mm
diameter of the wire is d = 1.047 mm