All categories

3 years ago

A 20 kg cart moving at 4 m/s has how much momentum?

Physics

1 answer:

masha68 [24]3 years ago

6 0

Answer:

We conclude that the required momentum is 80 kgm/s.

Explanation:

Given

Mass m = 20 kg

Velocity v = 4 m/s

To determine

The momentum p = ?

Important Tip:

The momentum of an object is the product of mass and velocity.

We can determine the momentum using the formula

$p = mv$

where

p is the momentum

m is the mass

v is the velocity

now substituting m = 20 and v = 4 using the equation

$p = mv$

$p = (20) (4)$

$p = 80$ kg m/s

Therefore, we conclude that the required momentum is 80 kgm/s.

You might be interested in

A 2 kg ball if at rest. If the ball accelerates to 20 m/s, what is the change in momentum?

katrin [286]

Answer:

change in momentum

20m/s x2=40kg/m

4 0

3 years ago

Is a process that modifies light waves so they vibrate in a single plane

madam [21]

The process you're fishing for is "polarization", but that's a

misleading description.

Polarization doesn't do anything to change the light waves.

It simply filters out (absorbs, as with a polarizing filter) the

light waves that aren't vibrating in the desired plane, and

allows only those that are to pass.

The intensity of a light beam is always reduced after

polarizing it, because much (most) of the original light

has been removed.

A laser light source may be thought of as an exception,

since everything coming out of the laser is polarized.

8 0

4 years ago

A 6.99-g bullet is moving horizontally with a velocity of +341 m/s, where the sign + indicates that it is moving to the right (s

Ratling [72]

Answer:

a). 1.218 m/s

b). R=2.8 $^{-3}$

Explanation:

$m_{bullet}=6.99g*\frac{1kg}{1000g}=6.99x10^{-3}kg$

$v_{bullet}=341\frac{m}{s}$

Momentum of the motion the first part of the motion have a momentum that is:

$P_{1}=m_{bullet}*v_{bullet}$

$P_{1}=6.99x10^{-3}kg*341\frac{m}{s} \\P_{1}=2.3529$

The final momentum is the motion before the action so:

a).

$P_{2}=m_{b1}*v_{fbullet}+(m_{b2}+m_{bullet})*v_{f}}$

$P_{2}=1.202 kg*0.554\frac{m}{s}+(1.523kg+6.99x10^{-3}kg)*v_{f}$

$P_{1}=P_{2}$

$2.529=0.665+(1.5299)*v_{f}\\v_{f}=\frac{1.864}{1.5299}\\v_{f}=1.218 \frac{m}{s}$

b).

kinetic energy

$K=\frac{1}{2}*m*(v)^{2}$

Kinetic energy after

$Ka=\frac{1}{2}*1.202*(0.554)^{2}+\frac{1}{2}*1.523*(1.218)^{2}\\Ka=1.142 J$

Kinetic energy before

$Kb=\frac{1}{2}*mb*(vf)^{2}\\Kb=\frac{1}{2}*6.99x10^{-3}kg*(341)^{2}\\Kb=406.4J$

Ratio = $\frac{Ka}{Kb}$

$R=\frac{1.14}{406.4}\\R=2.8x10^{-3}$

3 0

3 years ago

On what principle does a bottle opener work

Vsevolod [243]

Answer:

Bottle opener works on a fulcrum.

Explanation:

A bottle opener is a second-class lever because the pivot point is at one end of the opener and the load is in the middle.

8 0

3 years ago

Sea floor spreading could produce A) an ocean B) a mountain range C) a volcano D) a single fault-block mountain

lesya692 [45]

I think it is A. An Ocean

5 0

3 years ago