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Sergeeva-Olga [200]
3 years ago
5

A 20 kg cart moving at 4 m/s has how much momentum?

Physics
1 answer:
masha68 [24]3 years ago
6 0

Answer:

We conclude that the required momentum is 80 kgm/s.

Explanation:

Given

  • Mass m = 20 kg
  • Velocity v = 4 m/s

To determine

The momentum p = ?

Important Tip:

  • The momentum of an object is the product of mass and velocity.

We can determine the momentum using the formula

p = mv

where

  • p is the momentum
  • m is the mass
  • v is the velocity

now substituting m = 20 and v = 4 using the equation

p = mv

p = (20) (4)

p = 80 kg m/s

Therefore, we conclude that the required momentum is 80 kgm/s.

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A car travels 48 km in 1.2 hours. What is the average speed of the car in km/hr
Alborosie

Answer:

average speed of car is 40 km/h

Explanation:

if car goes 48 km per 1.2 hours , the car goes 40 km per hour. so average speed of car is 40km/h

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Calculate the kinetic energy in joules of a 1,500 kg car that is moving at a speed of 42 km/h
Rzqust [24]
Data:
KE (Kinetic Energy) = ? (Joule)
m (mass) = 1500 Kg 
v (speed) = 42 Km/h
converting to m/s (42 / 3.6), we have: v (speed) = 11.6 m/s

Formula:
K_{E} =   \frac{1}{2} m*v^2

Solving:
K_{E} = \frac{1}{2} m*v^2
K_{E} =  \frac{1}{2} *1500*(11.6)^2
K_{E} = \frac{1}{2} *1500*134.56
K_{E} =  \frac{201840}{2}
\boxed{\boxed{K_{E} = 100920\:Joule}}\end{array}}\qquad\quad\checkmark





4 0
3 years ago
Sharks and related fish can sense the extremely weak electric fields emitted by their prey in the surrounding waters. These dete
Sonja [21]

Answer

2) 1.5×10-2 m

Explanation

The potential difference is related to the electric field by:

\Delta V=Ed (1)

where

\Delta V is the potential difference

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d is the distance

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when connected to a battery with potential difference

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5 0
3 years ago
A 0.2-kg steel ball is dropped straight down onto a hard, horizontal floor and bounces straight up. The ball's speed just before
nadya68 [22]

Answer:

Explanation:

Given

mass of steel ball m=0.2\ kg

initial speed of ball u=10\ m/s

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therefore impulse J is given by

J=\Delta P

\Delta P=m(v-u)

\Delta P=0.2(-10-10)

\Delta =-4\ N-s

so magnitude of Impulse =4 N-s

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