There is a displacement. Just because the ball is thrown up,
and not crossways, doesn't mean its location is not moving. Remember, positive
displacement is together a displacement in the direction east, right, and up.
The velocity is the distance over time. To compute that, you must look how high
the ball moved before falling back down. Acceleration is expected to be
constant at 9.80m/s^2. That is the force of gravity. But remember that you are disregarding
air friction when you are computing the acceleration.
Answer:
Partial Pressure of F₂ = 1.30 atm
Partial pressure of Cl₂ = 0.70 atm
Explanation:
Partial pressure for gases are given by Daltons law.
Total pressure of a gas mixture = sum of the partial pressures of individual gases
Pt = P(f₂) + P(cl₂)
Partial pressure = mole fraction × total pressure
Let the mass of each gas present be m
Number of moles of F₂ = m/38 (molar mass of fluorine = 38 g/Lol
Number of moles of Cl₂ = m/71 (molar mass of Cl₂)
Mole fraction of F₂ = (m/38)/((m/38) + (m/71)) = 0.65
Mole fraction of Cl₂ = (m/71)/((m/38) + (m/71)) = 0.35 or just 1 - 0.65 = 0.35
Partial Pressure of F₂ = 0.65 × 2 = 1.30 atm
Partial pressure of Cl₂ = 0.35 × 2 = 0.70 atm
Answer: Because of Inertia
Explanation: According to Newton first law, that a body in a linear motion will continue to be in motion except an external for act on it
But also, a body in motion will always like to continue in motion and have a reluctance tendency to stop because of inertia.
the crash test dummies' bodies will continue to move forward even though the car stopped because of inertia.
Answer:
ffcvghnvb vyhgyhvthbgvgybn ytvg dfvthgbhtfgybhvtgbyhnt vfyhn fgb fvb
Explanation:
The first rule of vectors is that the horizontal and vertical components are separate. Disregarding air resistance, the only thing we have to worry about is gravity.
The appropriate suvat to use for the vertical component is v = u +at
I will take a to be -9.81, you may have to change it to be 10 if your qualification likes g to be 10.
v = 30 + (-9.81x2)
v = 30 - 19.62
=10.38m/s
Therefore we know that after 2.0 s the vertical component will be 10.38ms^-1, ie 10m/s as the answers given are all to 2sf.
The horizontal component is completely separate to the vertical component and since there is no air resistance, it will remain constant throughout the projectiles trajectory. Therefore it will remain at 40ms^-1.
Combining this together we get:
(1) vx=40m/s and vy=10m/s
