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dimaraw [331]
3 years ago
6

Suppose a 50 turn coil lies in the plane of the page in a uniform magnetic field that is directed into the page. The coil origin

ally has an area of 0.325 m^2. It is squished to have no area in 0.225 s. What is the magnitude of the average induced emf in volts if the uniform magnetic field has a strength of 1.5 T?
Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

EMF = 108.3 Volts

Explanation:

As per Faraday's law of electromagnetic induction we know that rate of change in magnetic flux will induce EMF in closed loop

So it is given as

EMF = N\frac{d\phi}{dt}

EMF = N\frac{BA - 0}{\Delta t}

now we know that

N = 50 turns

B = 1.5 T

A = 0.325 m^2

\Delta t = 0.225 s

now we have

EMF = (50)(\frac{1.5\times 0.325}{0.225})

EMF = 108.3 Volts

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F=27.39N

Explanation:

Take sum of torques at the point the step touches the wheel, that eliminates two torques

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Since we are looking for when the wheel just starts to rise up N-> 0 so no torque due to normal force

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Answer:

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