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zimovet [89]
2 years ago
9

How fast was a plane flying if it traveled 500 km in 30 min?

Physics
2 answers:
anyanavicka [17]2 years ago
8 0

Answer:

16.7 km per min

Explanation:

divided 500 and 30

vazorg [7]2 years ago
5 0
16.666 (keeps going)
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A man jogs at a speed of 1.6 m/s. His dog
FromTheMoon [43]
I believe it is
1.6x=2.7(x-1.8)
1.1x=2.7*1.8
x~4.4
4.4*1.6
~7.1m
5 0
3 years ago
An electric toy with a resistance of 2.50 Ω is operated by a 3.00-V battery. (a) What current does the toy draw? (b) Assuming th
Leno4ka [110]

Answer:

a) The current is i = 1.2 A

b) The charge is Q = 17280 C

c) The energy is E = 43200 J

Explanation:

a) The current is given by the ohm's law wich is:

i = V/R = 3/2.5 = 1.2 A

b) Since the charge is steady we can use the following equation to find the charge amount in that time:

i = Q/t

Q = t*i

Where t is in seconds, so we have 4h * 3600 = 14400 s

Q = 1.2*14400 = 17280 C

c)  The energy is the power delivered to the toy multiplied by the time:

P = 1.2*2.5 = 3 W

E = P*t = 3*14400 = 43200 J

7 0
3 years ago
What should a free-body diagram look like for a skydiver who has opened his parachute and is now slowing down as he falls?
mote1985 [20]
The last choice. Two arrows and the arrow up is shorter than the arrow down. Since the guy is falling and he’s opened his chute, he’s slowing down but he’s still falling meaning the force of gravity is stronger than the air resistance.
8 0
3 years ago
Read 2 more answers
If the surface of the conductor increases 4 times what will happen to the electrical resistance?​
marishachu [46]

Answer:

Increases

Explanation:

Higher current Higher resistance

Directly proportianal to each other

5 0
3 years ago
How much heat is needed to raise the temperature of 8g of water by 15oC?
Murrr4er [49]
<h2>Answer: 502.08 J</h2>

Explanation:

The heat (thermal energy) needed in to raise the temperature in a process can be found using the following equation:

Q=m.C.\Delta T   (1)

Where:

Q is the heat

m=8 g is the mass of the element (<u>water</u> in this case)

C is the specific heat capacity of the material. In the case of water is C=4.184\frac{J}{g\°C}

\Delta T=15\°C is the variation in temperature  <u>(which is increased in this case)</u>

Knowing this, let's rewrite (1) with these values:

Q=(8 g)(4.184\frac{J}{g\°C})(15\°C)  (2)

Finally:

Q=502.08 J  

5 0
3 years ago
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