<span>We simplify the equation to the form, which is simple to understand
<span>q+2/5=2q-11/7
Simplifying:
<span>q + 0.4=2q-11/7
Simplifying:
<span>q + 0.4=2q-1.57142857143
We move all terms containing q to the left and all other terms to the right.
<span>+1q-2q=-1.57142857143-0.4
We simplify left and right side of the equation.
<span>-1q=-1.97142857143
We divide both sides of the equation by -1 to get q.
<span>q=1.97142857143</span></span></span></span></span></span></span>
x = 
subtract 4x from both sides of the equation
6x - 4x - 2 = 13
2x - 2 = 13
add 2 to both sides
2x = 13 + 2 = 15
divide both sides by 2
x = 
Answer:
a) k
= 3.6 N/m ; b) 9.43 * 10¹²; c) 1.18 * 10¹¹; d) 75.08 N/m
Step-by-step explanation:
Length of iron bar = L = 2.7m;
side length of cross section = a = 0.07cm = 0.0007m;
x = 2.7 cm = 0.027m;
m = 100kg;
ρ = 7.87gm/cm³;
da = 2.28 * 10⁻¹⁰m;
a)
Fnet = F - mg
where Fnet = 0
So,
F = mg where F=k
x
k
= mg/x = 100*9.8/0.027
k
= 3.6 N/m
b)
Nchain = Aw/Aa =a²/(da)²
= (o.ooo7)²/(2.28 * 10⁻¹⁰)²
= 9.43 * 10¹²
c)
Nbond = L/da = 2.7/2.28 * 10⁻¹⁰
= 1.18 * 10¹¹
d)
Spring stiffness of wire = ksi = (Nbondk
)/Nchain
= [(1.18* 10¹¹)(6*10⁴)]/(9.43 * 10¹²)
= 75.08 N/m
Answer: First, write the equation,
t² - 15 = 0
Now, we shift the (-15) to RHS,
t² = 15
So, t = - √15 = -3.87 or + √15 = + 3.87