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Nesterboy [21]
4 years ago
5

Can someone please help me again ..

Mathematics
1 answer:
Naddik [55]4 years ago
7 0
64/4 = x/3 or 4/64 = 3/x
X= 16

3x16 = 48

The answer is 48

If you can, can you mark me as brainliest, I really appreciate it!
You might be interested in
if melissa placed an order for garden gloves ($2.99 each), and rakes (for $16.99 each), and she ordered three times as many glov
ICE Princess25 [194]
G:$2.99
R:$16.99

For every 1R we have 3G.
1R+3G=$16.99+3($2.99)
So 1R+3G=$25.96

If we take $129.80÷$25.96, we get 5.
So let's try 5.

5R+15G=5($16.99)+15($2.99)
So 5R+15G=$129.80



5 0
3 years ago
ellie brought s sponges there were 10 sponges in each package write an expression that shows how many packages ellie brought
In-s [12.5K]
S x 10. S stands for the packages of sponges, and 10 stands for the number of sponges in each package. I hope this helps!
3 0
3 years ago
Read 2 more answers
ALL THE POINTS I HAVE LEFT PLZ HELP
Blizzard [7]

Answer:

C

Step-by-step explanation:

r=5t

r squared=25t squared

area=pi r squared

so, A(r(t))=25(pi)(t squared)

3 0
3 years ago
I Needham help without this one I will give you brainlist
Semmy [17]

Answer:

hi, it can be 0 or also 1

please mark as brainiest:)

8 0
3 years ago
Read 2 more answers
On what intervals is the graph of f(x)=x^3-2x^2+5x+1 increasing?
amid [387]
f(x)=x^3-2x^2+5x+1\\ f'(x)=3x^2-4x+5\\
3x^2-4x+5=0\\\Delta=(-4)^2-4\cdot3\cdot5=16-60=-44
\Delta0 \Rightarrow the graph of the parabola is above the x-axis, so the derivative is always positive and therefore the initial function is increasing in its whole domain.

f(x)=0.5x^2-6\\
f'(x)=x
The function is decreasing when its first derivative is negative. The first derivative of this function is negative for x so for x\in(-\infty,0) the function is decreasing.

f(x)=\dfrac{x+1}{x-1}\qquad(x\not=1)\\
f'(x)=\dfrac{x-1-(x+1)}{(x-1)^2}=-\dfrac{2}{(x-1)^2}
The function is increasing when its first derivative is positive. The first derivative of this function is always negative therefore this function is never increasing.


3 0
4 years ago
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