Let a, b, and c be the times each pump will fill the tank when working alone.
Therefore, in 1 hour;
1/a +1/b = 1/(6/5) = 5/6 ---- (1)
1/a+1/c = 1/(3/2) = 2/3 ---- (2)
1/b+1/c = 1/(2) = 1/2 ---- (3)
From equation (1)
1/a = 5/6-1/b
Substituting for 1/a in eqn (2)
5/6-1/b+1/c = 2/3
-1/b +1/c = -1/6 => 1/c = 1/b - 1/6 --- (4)
Using eqn (4) in eqn (3)
1/b+1/b-1/6 = 1/2
2/b-1/6 = 1/2
2/b =1/2+1/6 = 2/3
1/b = 1/3
Then,
1/c = 1/3 - 1/6 = 1/6
1/a = 5/6 - 1/3 = 1/2
This means, in 1 hour and with all the pumps working together, the tank will be filled to;
1/a+1/b+1/c = 1/2+1/3+1/6 = 1 (filled fully).
Therefore, it will take 1 hour to fill the tank when all pumps are working together.
Answer:
y²+4y
Step-by-step explanation:
y multiplies with (y+4)
y times y is y²
y times 4 is 4y
That leaves you with y²+4y
The total number of minutes for all casses is 150 minutes
Answer:
the value of the series;
C) 59
Step-by-step explanation:
Recall that;
Therefore, we can evaluate the series;
by summing the values of the series within that interval.
the values of the series are evaluated by substituting the corresponding values of k into the equation.
So, the value of the series;
Answer:
-4 1/6
Step-by-step explanation:
