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3 years ago

Spin a spinner numbered 1-8 two times, land on two the first time and

2 answers:

8 0

The <u>correct probability</u> is 1/16.

Explanation:

There is 1 section marked 8 out of 8 sections. This makes the probability of landing on an 8 1/8.

The factors of 4 on this spinner are 1, 2, 4 and 8. This makes 4 sections out of 8, which makes the probability of landing on a factor of 8 equal 4/8=1/2.

Together, the probability of both events would be 1/8(1/2) = 1/16.

11111nata11111 [884]3 years ago

8 0

Answer:

Required probability = 1/16

Step-by-step explanation:

When we spin a spinner numbered 1-8, we find that each spin is independent of the other.

HEnce probability for getting any number from 1 to 8 will be equal to 1/8 and remain the same for each spin.

So Probability on two for the first time and factor of 8 on the second time

=Prob (landing on 2)*Prob (landing on any factor of 8)

P(landing on 2) = 1/8

Factors of 8 are 1,2,4,8

Prob (landing on factor of 8) = 4/8

Hence required prob = 1/8(4/8) =1/16

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Answer:

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2 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

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3 years ago

Give two reasons why it's impossible to draw triangle PQR m angle Q=103^ m angle R=47^ p = 44 q = 12 , and f = 31

Black_prince [1.1K]

Answer:

It is impossible becuase it would not eqaul the numbers a regular triangles would have. A triangle has to equal a certain number and this number does not make a traingle.

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2 years ago

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Can somebody help me solve for x?

Dahasolnce [82]

Let y = the distance between the top left corner and the bottom right corner

y^2 = 24^2 + 15^2

y^2 = 801

y = 3 * sqrt(89)

Now we can find x.

12^2 + x^2 = (3 * sqrt(89))^2

x^2 = 657

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2 years ago

Which expression represent a number that is one fourth as great as 10-2

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3 years ago

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