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3 years ago

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What is the data point that is the farthest from other data points when the box plot is NOT symmetrical?

1 answer:

Naddika [18.5K]3 years ago

5 0

Answer: B. Outlier

Step-by-step explanation:

An outlier is an extremely large or extremely small data value in a data set such that it appears far from the other data points when we plot data points on scatter plot or box plot.

Thus, the data point that is the farthest from other data points when the box plot is NOT symmetrical is Outlier.

Its presence affects the value of mean directly. So when a data set have outliers , we prefer Median(Mid value of a data set) as the best measure of central tendency because existence of outliers does not effect Median .

Hence, the correct option is B. Outlier.

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What is 1x+3y=18 in slope intercept form

photoshop1234 [79]

Answer:

y = -x/3 + 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

<u>Algebra I</u>

Standard Form: Ax + By = C

Slope-Intercept Form: y = mx + b

m - slope
b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Standard Form: x + 3y = 18

<u>Step 2: Rewrite</u>

<em>Find slope-intercept form</em>

Subtract <em>x</em> on both sides: 3y = -x + 18
Divide 3 on both sides: y = -x/3 + 6

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Step-by-step explanation:

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How do I do this please help

Umnica [9.8K]

Answer:

wrong as his calculation was incorrect at initial level itself when he found the result of the division

Step-by-step explanation:

Andre said

3 ÷ $\frac{2}{3}$

$=3 \times \frac{3}{2}$

$=\frac{3 \times 3}{2}$

$=\frac{9}{2}$

but andre calculated it as

$=4\tfrac{1}{3}$

$=\frac{4 \times 3 + 1}{3}$

$=\frac{13}{3}$

Hence his calculation was incorrect at initial level itself

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