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oee [108]
4 years ago
8

What is the specific name for a regular quadrilateral?

Mathematics
2 answers:
vesna_86 [32]4 years ago
3 0

The specific name for a regular quadrilateral is a polygon

Semenov [28]4 years ago
3 0
<span>A quadrilateral is a polygon with four sides. So a regular quadrilateral is a shape that has four equal sides, with all the interior angles equal. The more common name for this shape is a square!

~cutie</span>
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Find the distance between (16,12) and (0,0)
Natasha_Volkova [10]

Answer:

3/4 using equation y2-y1/x2-x1

Step-by-step explanation:

Use the equation y2-y1/x2-x1

x1, y1  x2, y2

(16,12) (0,0)

0-12/0-16= -12/-16= 3/4

7 0
3 years ago
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
5. Explain how you could use compatible numbers to estimate 245 ÷ 3. Then estimate the quotient.​
sdas [7]

Answer:

8

Step-by-step explanation:

Compatible numbers are defined as the numbers which are very close to the numbers that they are replacing that divides evenly into each other.

In the context, we have to estimate the quotient using the compatible numbers in order to estimate 245 divided by 3.

So, estimating 245 as 240 and 3 as 30.

Here, 240 is very close to 245 and 30 is close to 3. So the quotient is the result when we divide 240 by 30 and it divides evenly into 240.

We first divide the non zero parts of each number i.e. 24 by 3 to get the first part of the estimate.

Then we add on the zero if there were left in the problem to get your estimate.

Therefore,

240 / 30 = 8

So here, the quotient is estimated as 8.  

4 0
3 years ago
what number could be included in the data set 9,12,17,15,13 so the MEDIAN of the numbers in the set results in 14?
Georgia [21]

<em><u>Your answer is 12,17,15,13 if you take out the 9 your median will be 14.</u></em>


~*"AUBA14"*~

6 0
4 years ago
Read 2 more answers
A metalworker has a metal alloy that is 20​% copper and another alloy that is 60​% copper. How many kilograms of each alloy shou
tester [92]
132% that what your answer going to be
7 0
3 years ago
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