Answer:
C
Step-by-step explanation:
Answer:
t=5.5080( to 3 d.p)
Step-by-step explanation:
From the data given,
n =20
Deviation= 34/20= 1.7
Standard deviation (sd)= 1.3803(√Deviation)
Standard Error = sd/√n
= 1.3803/V20 = 0.3086
Test statistic is:
t = deviation /SE
= 1.7/0.3086 = 5.5080
ndf = 20 - 1 = 19
alpha = 0.01
One Tailed - Right Side Test
From Table, critical value of t =2.5395
Since the calculated value of t = 5.5080 is greater than critical value of t = 2.5395, the difference is significant. Reject null hypothesis.
t score = 5.5080
ndf = 19
One Tail - Right side Test
By Technology, p - value = 0.000
Since p - value is less than alpha , reject null hypothesis.
Conclusion:
From the result obtained it can be concluded that ,the data support the claim that the mean rating assigned to the wine when the cost is described as $90 is greater than the mean rating assigned to the wine when the cost is described as $10.
4(x+2)+2=14
4x+8+2=14
4x+10=14
Subtract 10 from both sides
4x=4
Divide by 4 on both sides
x=1
Answer:
Should be around 4.5
Step-by-step explanation:
If you round 31.53 to the nearest ten dollars, you get 30, 15 percent of 30 is 4.5
2(5x-15) + 2(2x+7) =0
10x-30+4x+14 = 0
14x = 16
x = 8/7
