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3 years ago

Find p(t, the x component of the total momentum of the system at time t. express your answer in terms of m1, m2, v1(t, and v2(t.

Physics

1 answer:

denpristay [2]3 years ago

6 0

The X-component of the momentum of the system is $\boxed{{p_x}={m_1}{v_1}\left(t\right)+{m_2}{v_2}\left(t\right)}$ .

Further Explanation:

The momentum of a body is the amount of motion contained by the body. The momentum of a body is expressed as the product of the mass and velocity of the body at the particular instant.

The momentum of the body is represented as:

$\boxed{p=m\times v}$

For a system of particles, the momentum of the whole system is the vector sum of individual momentum of all the particles.

${\vec p_{net}}={\vec p_1}+{\vec p_2}+{\vec p_3}.....$

Here, ${\vec p_{net}}$ is the net momentum of the system.

In the given question, both the particles are moving in the same direction i.e. X-direction. Therefore, the net momentum of the system in X-direction is the sum of the two momentum.

The velocity of the first particle at time $t$ is ${v_1}\left(t\right)$ .

The momentum of the first particle is:

${p_1}={m_1}{v_1}\left(t\right)$

The velocity of the second particle at time $t$ is ${v_2}\left(t\right)$ .

The momentum of the second particle is:

${p_2}={m_2}{v_2}\left(t\right)$

The X-component of the net momentum of the system is:

$\begin{aligned}{p_x}&={p_1}+{p_2}\\&={m_1}{v_1}\left(t\right)+{m_2}{v_2}\left(t\right)\\\end{aligned}$

Thus, the X-component of the momentum of the system is $\boxed{{p_x}={m_1}{v_1}\left(t\right)+{m_2}{v_2}\left(t\right)}$ .

Learn More:

1. You are riding on a roller coaster that starts from rest at a height of 25.0 m and moves down a frictionless track brainly.com/question/10177389

2. A 700-kg car, driving at 29 m/s, hits a brick wall and rebounds with a speed of 4.5 m/s brainly.com/question/9484203

3. A 50-kg meteorite moving at 1000 m/s strikes earth. Assume the velocity is along the line joining earth's center brainly.com/question/6536722

Answer Details:

Grade: High School

Subject: Physics

Chapter: Force and Momentum

Keywords:

Momentum, X-component, total momentum, isolated system, velocity of the particle, v1(t), v2(t), composed of two blocks, masses m1 and m2.

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Basile [38]

Yo I wish I was at higheschool and I think the last one is darker or the same cause of the reflection

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3 years ago

What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2400 kg car (a large car

makvit [3.9K]

Answer:

Fm= 91.88 N

Explanation:

Pascal principle

The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.

The pressure is definited like this:

P=F/A

Where:

P: Pressure in pascals (Pa)

F: Force acting in the area (N)

A : Area where the force acts (m²)

Pascal principle

Pm=Ps

Fm/ Am= Fs/ As Formula (1)

Where :

Pm : Pressure on the master piston

Ps : Pressure on the slave piston

Fm : Force on the master piston (N)

Fs: Force on the slave piston ((N)

Am: master piston area (m²)

As: slave piston area (m²)

Area Formula (A)

A= π*R²

R : piston radius

Calculation of the weight of the car (W)

W= m*g= 2400 kg*9.8m/s²= 23520 N

W = Fs

Data

Fs = 23520 N

Dm = 1.5 cm

Ds = 24 cm

Rm = 0.75 cm

Rs = 12 cm

Am = π*Rm² = π*(0.75)²

As = π*Rs² = π*(12)²

Force exerted on the master cylinder

We replace data in the formula (1)

$\frac{F_{m} }{A_{m} } = \frac{F_{s} }{A_{s} }$

$F_{m} = \frac{F_{s}*A_{m} }{A_{s}}$

$F_{m} = \frac{(23520 N)*(\pi *(0.75)^{2})(cm^{2})}{(\pi *(12)^{2})(cm^{2})}$

$F_{m} = (23520 N)*\frac{(0.75)^{2} }{(12)^{2} }$

Fm= 91.88 N

8 0

3 years ago

I need to explain how objects can have the same volume but different mass. Help??

kaheart [24]

No problem, and you already know all about it.

Here are a few examples of same volume / different weight:

-- A bottle full of water is heavier than the same bottle when it's full of air.
-- Stones are heavier than styrofoam chunks the same size.
-- A bowl of meat loaf is heavier than a bowl of scrambled eggs.

In each example, two things have the same volume, but one weighs more than
the other. I didn't say anything about mass yet, but that's easy: As long as you
keep everything on Earth, more weight means more mass.

So how come, in each example, things with the same volume have different mass ?
This was your original question.

The answer is just the simple fact that there are millions of different substances, and
each different substance packs a different amount of mass into the same volume.

The amount of mass that a substance packs into a standard volume is called
the density of the substance. Meat loaf is more dense than scrambled eggs.
Stone is more dense than styrofoam. Water is more dense than air. And gold
is 19 times as dense as water. If you have a jar that holds a pound of water, and
you pour out the water and fill the jar with gold, the same jar holds 19 pounds of gold,
because the density of gold is 19 times the density of water.

The reason you were assigned to think about this question for homework is that
next time your Physics class meets, you'll start talking about Density.  And you're
all ready for it now.

6 0

4 years ago

A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t

MrRissso [65]

Answer:

a) T = 608.22 N

b) T = 608.22 N

c) T = 682.62 N

d) T = 533.82 N

Explanation:

Given that the mass of gymnast is m = 62.0 kg

Acceleration due to gravity is g = 9.81 m/s²

Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.

So;

To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;

T = mg

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs the rope at a constant rate tension in the string is

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs up the rope with an upward acceleration of magnitude

a = 1.2 m/s²

the tension in the string is T - mg = ma (Since acceleration a is upwards)

T = ma + mg

= m (a + g )

= (62.0 kg)(9.81 m/s² + 1.2 m/s²)

= (62.0 kg) (11.01 m/s²)

= 682.62 N

When the gymnast climbs up the rope with an downward acceleration of magnitude

a = 1.2 m/s² the tension in the string is mg - T = ma (Since acceleration a is downwards)

T = mg - ma

= m (g - a )

= (62.0 kg)(9.81 m/s² - 1.2 m/s²)

= (62.0 kg)(8.61 m/s²)

= 533.82 N

5 0

3 years ago

A bat at rest sends out ultrasonic sound waves at 46.2 kHz and receives them returned from an object moving directly away from i

murzikaleks [220]

Answer:

f" = 40779.61 Hz

Explanation:

From the question, we see that the bat is the source of the sound wave and is initially at rest and the object is in motion as the observer, thus;

from the Doppler effect equation, we can calculate the initial observed frequency as:

f' = f(1 - (v_o/v))

We are given;

f = 46.2 kHz = 46200 Hz

v_o = 21.8 m/s

v is speed of sound = 343 m/s

Thus;

f' = 46200(1 - (21/343))

f' = 43371.4285 Hz

In the second stage, we see that the bat is now a stationary observer while the object is now the moving source;

Thus, from doppler effect again but this time with the source going away from the obsever, the new observed frequency is;

f" = f'/(1 + (v_o/v))

f" = 43371.4285/(1 + (21.8/343))

f" = 40779.61 Hz

4 0

3 years ago