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andrew-mc [135]
3 years ago
12

The factored form of 4a3b5 − 16a5b2 + 12a2b3 is ?

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
7 0
4a^2b^2(ab^3-4a^3+3b)
yulyashka [42]3 years ago
7 0

Answer:

The factored form of 4a^3b^5-16a^5b^2+12a^2b^3 is 4a^2b^2\left(ab^3-4a^3+3b\right).

Step-by-step explanation:

To find the factored form of 4a^3b^5-16a^5b^2+12a^2b^3 you must:

Apply exponent rule: a^{b+c}=a^ba^c

a^2b^3=a^2b^2b,\:a^5b^2=a^2a^3b^2,\:a^3b^5=a^2ab^2b^3

So, we can write our expression as 4a^2ab^2b^3-16a^2a^3b^2+12a^2b^2b.

Next, rewrite 12 as 3\cdot \:4 and -16 as 4\cdot \:4

4a^2ab^2b^3+4\cdot \:4a^2a^3b^2+3\cdot \:4a^2b^2b

Factor out common term: 4a^2b^2

Therefore,

4a^3b^5-16a^5b^2+12a^2b^3= 4a^2b^2\left(ab^3-4a^3+3b\right)

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Step-by-step explanation:

this triangle is regular one

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