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3 years ago

When chords intersect in a circle, the vertical angles formed intercept congruent arcs.

Mathematics

2 answers:

sasho [114]3 years ago

8 0

Answer: Sometimes

Step-by-step explanation: Chords do intersect in a circle but not all the time.

BlackZzzverrR [31]3 years ago

7 0

The answer is sometimes

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Jake plotted an equivalent ratio on the coordinate grid below:

MakcuM [25]

Answer:

(A) If the number of cups of cereal is 40, then the number of cups of raisins will be 10.

Step-by-step explanation:

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2 years ago

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What is the range of the function y = -3cosx - 1?

Bingel [31]

Range of y = -3 cosx -1 is -4 < y < 2

8 0

4 years ago

Find derivative problem Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

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3 years ago

Which of the following is equivalent to (x^4/3 x^2/3)^1/3

Reika [66]

Answer:

The answer is2nd point

Step-by-step explanation:

${n}^{a} \times {n}^{b} = {n}^{a + b}$

(x^4/3)×(x^2/3) = x^(4/3 + 2/3)

= x²

${( {n}^{a} )}^{b} = {n}^{ab}$

(x²)^1/3 = x^(2×1/3)

= x^2/3

7 0

3 years ago

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Find the product. (x2+3x+7)(x^7)= Please help :)

Nesterboy [21]

Answer: x^9+3x^8+7x^7

Step-by-step explanation:

the ^ mean the exponent

4 0

3 years ago