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ycow [4]
3 years ago
11

The Japanese 5 yen coin has a hole in the middle. If the diameter of the coin is 22 mm and the diameter of the hole is 5 mm, how

would you calculate in terms of es002-1.jpg how much longer the outer edge is than the inner edge?

Mathematics
2 answers:
mars1129 [50]3 years ago
7 0
To help you understand the problem, illustrate it first like that shown in the picture. What is asked is the distance between the outer edge and the inner edge (represented by the green arrow). That distance could be determined by getting the difference of the red and blue arrows, which represent the radii of the hole and the coin, respectively. 

Thus,

distance = (22/2) - (5/2) = 8.5 mm

alekssr [168]3 years ago
6 0

Answer:

A & D

Step-by-step explanation:

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Frank deposits his savings at the bank. After 3 years, it has earned $102 in interest, at a simple
Liula [17]

Answer:

1530

Step-by-step explanation:

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3 years ago
Which equation below is a direct variation?
masya89 [10]
Direct variation is of the form y = kx where k is a constant

So its A
5 0
3 years ago
simplify 1/6 divided by 5/9 (Write final answers in lowest terms and mixed numbers, if necessary.) and please explain
Mkey [24]

Answer:

\frac{3}{10}

Step-by-step explanation:

to divide 2 fractions follow the procedure

• Leave the first fraction

• Change division to multiplication

• Turn the second fraction upside down

• Simplify by cancelling common factors, if possible

\frac{1}{6} ÷ \frac{5}{9}

= \frac{1}{6} × \frac{9}{5} (cancel 6 and 9 by 3 )

= \frac{1}{2} × \frac{3}{5}

=\frac{1(3)}{2(5)}

= \frac{3}{10} ← in simplest form

The fraction is in simplest form when no factor apart from 1 divides into the numerator/ denominator




4 0
3 years ago
If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ? sin Θ = square root 2 ov
densk [106]

Answer:

\huge\boxed{\sin\theta=-\dfrac{\sqrt2}{2};\ \tan\theta=-1}

Step-by-step explanation:

We have:

\\cos\theta=\dfrac{\sqrt2}{2},\ \dfrac{3\pi}{2}

For sine use:

\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x

Substitute:

\sin^2\theta=1-\left(\dfrac{\sqrt2}{2}\right)^2\\\\\sin^2\theta=1-\dfrac{(\sqrt2)^2}{2^2}\\\\\sin^2\theta=1-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4}{4}-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4-2}{4}\\\\\sin^2\theta=\dfrac{2}{4}\to\sin\theta=\pm\sqrt{\dfrac{2}{4}}\\\\\sin\theta=\pm\dfrac{\sqrt2}{\sqrt4}\\\\\sin\theta=\pm\dfrac{\sqrt2}{2}

θ in IV quadrant, therefore sine is negative.

\sin\theta=-\dfrac{\sqrt2}{2}

For tangent use:

\tan x=\dfrac{\sin x}{\cos x}

Substitute:

\tan\theta=\dfrac{-\frac{\sqrt2}{2}}{\frac{\sqrt2}{2}}=-\dfrac{\sqrt2}{2}\cdot\dfrac{2}{\sqrt2}=-1

8 0
3 years ago
PLEASE HELP ME!!! In a recent election, there were six candidates and 5100 total votes. The circle graph below summarizes the vo
Crazy boy [7]
25.2:360 ::x:5100 
 Or 25.2 x ------=----- then cross multiply, 360x=5100*25.2 
7 0
3 years ago
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