Answer: "N" is considered as the size of the input that is being given in the algorithm.
Explanation: During a problem solving process , a algorithm is used to analyze the problem . Many function and steps are to be taken care of while analyzing algorithm. Among analyzing step, input is also given which is usually zero more than that . An input has a certain size which is given by the initial "N". The input size defines the length of the string for the input.
The answer would be B, for your computer is considered a client instead of server.
PSEUDOCODE:
1. DECLARE number: INTEGER
2. DECLARE multiple: INTEGER
3. INPUT number
4. FOR counter FROM 1 TO 10 DO
5. multiple <-- number * counter
6. PRINT number, " * ", counter, " = ", multiple
7. ENDFOR
<em>1. declaring a variable "number" as an Integer</em>
<em>2. declaring a variable "multiple" as an Integer</em>
<em>3. The user inputs the value of number</em>
<em>4. FOR loop where variable "counter" increments by 1 after every iteration</em>
<em>5. sets the value for variable "multiple" as the value of number * counter</em>
<em>6. prints out for example "3 * 1 = 3" and will continue till counter reaches 10</em>
<em>7. Ends the for loop</em>
FLOWCHART below
hope it helped
The most effective way to exploit TCP three-way handshake is TCP SYN flood.
- SYN flood attack is simply a kind of computer attack that begins with 3-way TCP handshake.
- TCP SYN flood is also called SYN flood and it is a type of distributed Denial of Service (DDoS) attack that uses every part of the normal TCP three-way handshake to eat up resources on the known server and render it non-functional
- With TCP SYN flood, a hacker can eat up resources of target's computer and makes it unresponsive.
From the above, we can therefore say that the most effective way to exploit TCP three-way handshake is TCP SYN flood.
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Explanation: