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tankabanditka [31]
3 years ago
5

All of the following are common symptoms of all dissociative disorders except

Physics
1 answer:
Sonbull [250]3 years ago
5 0
I believe it is A. Wandering away from home should be a symptom of dissociative disorders. Maybe check if I’m right. Sorry if I’m not.
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With what speed must m1 rotate in a circle of radius r if m2 is to remain hanging at rest?
11Alexandr11 [23.1K]
Velocity =2 pie*r/t
distance = 2 (pie) r
accelaretion =distance/t2
f=m*v2/r
v=square root of Fr/m

5 0
4 years ago
Which of the following describes a concave mirror. Select all that apply. Objects within the focal length will create real image
ahrayia [7]
Let's see sentence-by-sentence:

<span>- Objects within the focal length will create real images. --> false
In fact, objects within the focal length create virtual images, as it can be seen in the ray diagrams here:
https://upload.wikimedia.org/wikipedia/commons/4/47/Concavemirror_raydiagram_F.svg

- Concave mirrors converge distant parallel light rays on the focal point. --> TRUE: the parallel rays (with respect to the mirror's axis) are reflected back into the focal point of the mirror, as it can be seen also from the previous picture.

- Concave mirrors can only create real images. --> FALSE: as it can be seen from the first picture, when the object is between the focus and the mirror, its image is virtual.

Concave mirrors can create real and virtual images. --> TRUE: concave mirrors can create real and virtual images, depending on the position of the object.

- Objects far away from concave mirrors will appear enlarged. --> FALSE:
as it can be seen from the ray diagram, the size of the image is smaller than the size of the object. https://upload.wikimedia.org/wikipedia/commons/d/d2/Concavemirror_raydiagram_2F.svg

- Objects between the center of curvature and the focal point will create real images.--> TRUE: as it can be seen from the ray diagram (2F corresponds to the center of curvature), the image in this case is on the same side of the object, so it is real. </span>https://upload.wikimedia.org/wikipedia/commons/9/91/Concavemirror_raydiagram_2FE.svg
7 0
3 years ago
Read 2 more answers
What is the quantity of charge that passes through a conductor when there is a current of 0.25 A for 10 minutes?
nikitadnepr [17]
To calculate charge(Q) through a point, we multiply the current(I) with time (t)
Thus, Q= It
Therefore, t must be in SI units which gives 60*10 seconds.
Q=0.25A*600s= 150 coulombs.
4 0
3 years ago
A hockey puck moving at 28 m/s is caught by an 80,00 kg man who was at
zimovet [89]

Answer:

A

Explanation:

all the work is in the attached file :D

8 0
4 years ago
A particle of mass 4.0 kg is constrained to move along the x-axis under a single force F(x) = −cx3 , where c = 8.0 N/m3 . The pa
Pie

Answer:4.58 m/s

Explanation:

Given

mass of Particle m=4 kg

F=-cx^3

a=\frac{F}{m}

a=-\frac{cx^3}{m}

a=-\frac{8x^3}{4}

a=-2x^3

v\frac{\mathrm{d} v}{\mathrm{d} x}=-2x^3

vdv=-2x^3dx

integrating

\int_{6}^{v_b}vdv=\int_{1}^{-2}-2x^3dx

\frac{v_b^2-6^2}{2}=-\frac{1}{2}\left [ \left ( -2\right )^4-\left ( 1\right )^4\right ]

\frac{v_b^2-36}{2}=-0.5\times 15

v_b^2=36-15

v_b=\sqrt{21}

v_b=4.58 m/s

6 0
3 years ago
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