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2 years ago

How much energy is required to accelerate a golf ball of mass 0.046 kg initially at rest to a speed of 0.75c?

Physics

1 answer:

Andrew [12]2 years ago

3 0

The required energy to accelerate the golf ball is $0.232875X10^{16} kg-m/sec^2$ .

<h2>What is Energy?</h2>

Energy, which is observable in the execution of labor as well as in the form of light and heat, is the quantitative quality that is transmitted to an object or to a physical phenomenon in physics.
Energy is a preserved resource; according to the rule of conservation of energy, energy can only be transformed from one form to another and cannot be created or destroyed.
The joule, which is defined as "the energy transmitted to an object by the effort of moving it a length of one metre against a force of one newton," is the standard measure for power in the International System of Units (SI).

Given that,

E= $mc^2$

= $0.046X0.75^2Xc^2$

= $0.232875X10^{16} kg-m/sec^2$ .

Learn more about energy here:

brainly.com/question/13881533

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A car starting from rest moves with a constant acceleration of 10 mi/hr2 for 1 hour, then decelerates at a constant 5 mi/hr2 unt

Vinvika [58]

Answer:

The total distance traveled by the car (S) = 15 mi

Explanation:

Total acceleration ( $a_{1}$ ) = 10 mi / $h^{2}$

Time (t) = 1 hour

Deceleration ( $a_{2}$ ) = - 5 mi / $h^{2}$

From law of speed we know that V = u + $a_{1}$ t -----------(1)

Where V = Final speed

u = initial speed and t = time period

Car starts from rest so initial speed is zero so u = 0

Then equation 1 becomes V = $a_{1}$ t = 10 × 1 = 10 mi / h ---------(2)

The distance traveled by the car $S_{1}$ = u t + $\frac{1}{2}$ × $a_{1}$ × $t^{2}$ -------------(3)

Put all the values in equation we get $S_{1}$ = 0 + $\frac{1}{2}$ × 10 × $1^{2}$

$S_{1}$ = 5 mi ---------------(4)

This is the distance traveled by the car in 1 hour.

In second case when car starts decelerates the equation of motion becomes

⇒ V = u - a t -----------(5)

final speed in this case = 0 and initial speed (u) = 10 mi / h

⇒ 0 = 10 - 5 t

⇒ 5 t = 10

⇒ t = 2 hours

Distance traveled by the car in to hours $S_{2}$ = u t + $\frac{1}{2}$ × $a_{2}$ × $t^{2}$

⇒ $S_{2}$ = 10 × 2 - $\frac{1}{2}$ × 5 × $2^{2}$

⇒ $S_{2}$ = 20 - 10

⇒ $S_{2}$ = 10 mi

This is the distance traveled by the car in the next two hours.

Thus the total distance traveled by the car = $S_{1}$ + $S_{2}$

⇒ S = 5 + 10 = 15 mi

3 0

3 years ago

What is the unit for measuring energy

sdas [7]

This would be called a Joule. The formula for energy is P.E. = mgh (otherwise known as the gravitational force formula, which is energy.) M is the mass in kilograms, and G is the acceleration due to gravity, which is actually (9.8 m / s2 at the surface of the earth.) I hope this helps! ~Mia

7 0

3 years ago

A rotating wheel requires 5 s to rotate 38 revolutions. Its angular velocity at end of time interval 5-s is 79 rad/s. What is th

Lera25 [3.4K]

"Rotating wheel" is meant to indcate that the wheel is already rotating at the start. Denote the initial angular velocity by ω₀. Then the angular displacement θ at time t is

θ = ω₀t + 1/2 αt ²

while the angular velocity ω is

ω = ω₀ + αt

It takes 5 s for the wheel to rotate 38 times, or turn a total of (2π rad/rev) (38 rev) = 76π rad, as well as to reach an angular velocity of 79 rad/s, so that

76π rad = ω₀ (5 s) + 1/2 α (5 s)²

79 rad/s = ω₀ + α (5 s)

Solve the second equation for ω₀ and substitute into the first equation, then solve for α :

ω₀ = 79 rad/s - α (5 s)

==> 76π rad = (79 rad/s - α (5 s)) (5 s) + 1/2 α (5 s)²

==> 76π rad = (79 rad/s) (5 s) - 1/2 α (5 s)²

==> 1/2 α (5 s)² = (79 rad/s) (5 s) - 76π rad

==> α = ((79 rad/s) (5 s) - 76π rad) / (1/2 (5 s)²)

==> α ≈ 12.5 rad/s²

3 0

3 years ago

What is the second step of the decision-making process?

Reptile [31]

Answer:

A.Consider and evaluate the consequences of each choice

Explanation:

As you enter the decision-making proccess you would have to see the different options that you have, after this you just have to consider and evaluate the consequences of the different options that you have, in this phase you have to weight the consequences and what it would take to make those decisions.

6 0

4 years ago

Which of these is NOT a type of satellite?

Elanso [62]

<h2>Answer: A. land-based</h2>

Explanation:

An artificial satellite is one that is launched into space to orbit the Earth (or another body of the solar system) for various purposes.

In this sense, the characteristics of an artificial satellite will depend on its purpose and functionality. From there we can list: meteorological satellites (for weather) , telecommunications satellites, remote sensing satellites, global positioning systems satellites, environmental satellites, research satellites, among others.

In addition, their orbits can be classified according to their height and inclination, depending on the use they have.

On the other hand, one of the main conditions for a satellite to be considered as such is that it must be kept orbiting. This means, it must not touch land during its useful life, even if it remains in constant contact with its earth based control stations.

Therefore, a land-based is not a type of satellite.

5 0

3 years ago