Answer:
Induced current,
Explanation:
Given that,
Area of cross section of the wire,
Time, t = 2.2 s
Initial magnetic field,
Final magnetic field,
Resistance of the coil, R = 8 ohms
The expression for the induced emf is given by :
= magnetic flux
So, the induced emf in the loop is 0.023 volts. The induced current can be calculated using Ohm's law as :
So, the magnitude of the induced current in the loop of wire is . Hence, this is the required solution.
Answer:
Fission is the release of atomic energy related to the splitting of nuclei.
M = M1 + M2 + E where E = m c^2 energy from conversion of mass
if the daughter nuclei are less in total mass than the parent nucleus then the difference is released as atomic energy where E = m c^2 and m is the mass that has been lost in the conversion.
Answer:
Explanation:
First we have to find the time required for train to travel 60 meters and impact the car, this is an uniform linear motion:
The reaction time of the driver before starting to accelerate was 0.50 seconds. So, remaining time for driver is 1.5 seconds.
Now, we have to calculate the distance traveled for the driver in this 0.5 seconds before he start to accelerate. Again, is an uniform linear motion:
The driver cover 10 meters in this 0.5 seconds. So, the remaining distance to be cover in 1.5 seconds by the driver are 35 meters. We calculate the minimum acceleration required by the car in order to cross the tracks before the train arrive, Since this is an uniformly accelerated motion, we use the following equation:
Answer:
0.0001252
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Answer:
137.8 N
Explanation:
First we need to find the acceleration of the sprinter. To do so, we can use the Torricelli's equation:
V^2 = Vo^2 + 2*a*S
9^2 = 2^2 + 2*a*25
81 = 4 + 50a
50a = 77
a = 77/50 = 1.54 m/s2
Now, to find the resulting force in the sprinter, we can use the following equation:
Force = mass * acceleration
Force = 70 * 1.54 = 107.8 N
If we have a 30 N force against the sprinter, the total force applied is:
Resulting force = Applied force - Wind force
107.8 = Applied force - 30
Applied force = 137.8 N