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2 years ago

Do all metals stick to magnets? Give an example. I NEED HELP FASTT

Physics

1 answer:

ludmilkaskok [199]2 years ago

6 0

Answer:

Explanation:

Not all metals stick to magnets. Like aluminum. if you were to stick a magnet on to an aluminum it would fall off.

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What do all waves carry

MAVERICK [17]

Answer:

the waves carry energy

Explanation:

this is the way you can write it in short manner

hope it helps you.

MARK me as BRAINLIEST pls

5 0

2 years ago

In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.42 m. The mug

telo118 [61]

Answer:

a) $V_{x}=3.72m/s$ , b) ∠=-54.83°

Explanation:

In order to solve this problem, we must start with a drawing of the situation, this will help us visualize the problem better. (See picture attached).

Now, the idea is that the beer mug has a horizontal speed and no vertical speed at initial conditions. So knowing this, we can start finding the initial velocity of the mug.

In order to do so, we need to find the time it takes for the mug to reach the ground. We can find it by using the following equation:

$y=y_{0}+V_{y0}t+\frac{1}{2}a_{y}t^{2}$

We can see from the drawing that y and the initial velocity in y are zero, so we can simplify our formula:

$0=y_{0}+\frac{1}{2}a_{y}t^{2}$

so we can solve for t, so we get:

$t=\sqrt{\frac{-(2)y_{0}}{a}}$

so now we can substitute the known values, so we get:

$t=\sqrt{\frac{-(2)(1.42)}{-9.8}}$

which yields:

t=0.538s

So we can use this value to find the velocity in x:

$V_{x}=\frac{x}{t}$

When substituting we get:

$V_{x}=\frac{2m}{0.538s}$

which yields:

$V_{x}=3.72m/s$

In order to solve part b, we need to find the y-component of the velocity, for which we can use the following formula:

$\Delta y=\frac{V_{f}^{2}-V_{0}^{2}}{2a}$

We know that $V_{0}$ is zero, so we can simplify the expression:

$\Delta y=\frac{V_{yf}^{2}}{2a}$

So we can solve the equation for $V_{yf}^{2}$ so we get:

$V_{yf}=\sqrt{2\Delta y a}$

and when substituting the known values we get:

$V_{yf}=\sqrt{2(-1.42m)(-9.8m/s^{2})}$

which yields:

$V_{yf}=-5.28m/s$

Once we got the final velocity in y, we can use it together with the velocity in x to find the angle.

So we can use the following formula:

$tan \theta =\frac{V_{y}}{V_{x}}$

when solving for theta we get:

$\theta = tan^{-1}(\frac{V_{y}}{V_{x}})$

We can substitute so we get:

$\theta = tan^{-1}(\frac{-5.28m/s}{3.72m/s})$

which yields:

$\theta = -54.83^{o}$

7 0

3 years ago

A 7 kg object attached to a horizontal string moves with constant speed in a circle on a frictionless horizontal surface. The ki

Marizza181 [45]

Answer:

Explanation:

Given

mass of object $m=7 kg$

kinetic Energy $k=36\ J$

Tension in string $T=326\ N$

mass is moving in a horizontal circle so tension is providing the centripetal acceleration

therefore $T=\frac{mv^2}{r}----1$

where r=radius of circle

kinetic energy of particle $k=\frac{1}{2}mv^2----2$

divide 1 and 2 we get

$\frac{T}{k}=\frac{\frac{mv^2}{r}}{\frac{1}{2}mv^2}$

$\frac{T}{k}=\frac{2}{r}$

$r=\frac{2k}{T}=\frac{2\times 36}{326}$

$r=0.2208\ m$

8 0

3 years ago

Drag and drop the words into the correct locations to label the layers of the atmosphere, with the lowest layer at the bottom. (

professor190 [17]

Answer:

The top layer is exosphere. The fourth is the Thermosphere. The middle layer is the mesophere. The second layer is the Stratospere. the lowest layer is the troposphere

Explanation:

4 0

3 years ago

Read 2 more answers

The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 5.0 rev/s in 8.0 s. At thi

alisha [4.7K]

Answer:

The total number of revolution is 50 rev.

Explanation:

Given that,

Angular speed = 5.0 rev/s

Time = 8.0 s