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3 years ago

5

Do all metals stick to magnets? Give an example. I NEED HELP FASTT

1 answer:

ludmilkaskok [199]3 years ago

6 0

Answer:

No

Explanation:

Not all metals stick to magnets. Like aluminum. if you were to stick a magnet on to an aluminum it would fall off.

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Calculate the angular velocity and linear velocity of both wheels assuming the larger wheel rotates at 120 revolutions per mi

IRINA_888 [86]

<span>120 revolutions per min is (20RPM)
120revolutions is 240 Pi radians (because 1 revolution is 2Pi rad)

angular velocity
w= 240Pixf, f is the frequency and f= 1/T, T =1mn=60s=period, so f=1/60=0.01Hz
so w = 240*Pi*0.01=12.56 rad /s
linear velocity can be found with
V =Rx w,
V=12.56 R the value depends on what value is the radius of both wheels

</span>

6 0

3 years ago

A bicycle wheel with a radius of 0.42 m accelerates uniformly for 6.8 s from an initial angular velocity of 5.5 rad/s to a final

Art [367]

Answer:

The angular acceleration required is 0.1765 rad/ $s^2$

Explanation:

The radius of the bicycle wheel has a radius of 0.42 m.

The acceleration is for time, t = 6.8 seconds.

Initial angular velocity is given as $\omega_{0}$ = 5.5 rad/s

Final angular velocity is given as $\omega_{f}$ = 6.7 rad/s

Therefore from the formula for angular speed we get

$\omega_{f}$ = $\omega_{0}$ + ( $\frac{d\omega}{dt}$ $\times$ t), where t is the time in seconds.

Therefore we get

6.7 = 5.5 + (6.8 × $\frac{d\omega}{dt}$ )

Therefore we get the angular acceleration, $\frac{d\omega}{dt}$ = $\frac{(6.7 - 5.5 }{6.8} = 0.1765 rad/ s^2$

The angular acceleration required is 0.1765 rad/ $s^2$

8 0

3 years ago

Se deja resbalar por un plano inclinado de 30° un cuerpo de 15kg. Calcular la aceleración con la que desciende suponiendo que no

kupik [55]

Answer:

$4.9 m/s^2$

Explanation:

In order to find the acceleration of the block, we have to find the net force acting on it along the direction parallel to the incline.

However, there is only one force acting on the block along this direction: it is the component of the weight parallel to the plane, given by

$mg sin \theta$

where

m = 15 kg is the mass of the block

$g=9.8 m/s^2$ is the acceleration of gravity

$\theta=30^{\circ}$ is the angle of the incline

According to Newton's second law, the net force is proportional to the acceleration, a:

$F=ma$

So we can write:

$ma = mg sin \theta$

And so, the acceleration is:

$a=g sin \theta = (9.8)(sin 30^{\circ})=4.9 m/s^2$

7 0

3 years ago

Please help! 34 points!

solmaris [256]

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3 years ago

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How much money does a psychologist make?

Vikki [24]

Answer:

85,000 dollars

Explanation:

I searched it up.

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3 years ago

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