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3 years ago

Do all metals stick to magnets? Give an example. I NEED HELP FASTT

Physics

1 answer:

ludmilkaskok [199]3 years ago

6 0

Answer:

Explanation:

Not all metals stick to magnets. Like aluminum. if you were to stick a magnet on to an aluminum it would fall off.

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A motorcycle rides on the vertical walls around the perimeter of a large circular room. The friction coefficient between the mot

igomit [66]

Answer:

option D

Explanation:

given,

coefficient of friction between wall and tire = µ

speed of motorcycle = s

friction force = f = μ N

where normal force will be equal to centripetal force

$N = \dfrac{mv^2}{r}$

for motorcycle to not to slip weight should equal to the centripetal force

now,

$m g =\mu \dfrac{mv^2}{r}$

$\mu =\dfrac{rg}{s^2}$

where "rg" is constant

$\mu\ \alpha \ \dfrac{1}{s^2}$

$\mu\ \alpha \ s^{-2}$

Hence, the correct answer is option D

7 0

3 years ago

Which location would the selected items BEST fit on the nuclear energy diagram?

Sladkaya [172]

Your answer is c) Fusion

7 0

4 years ago

Read 2 more answers

A centrifuge has an angular velocity of 3,000 rpm, what is the acceleration (in unit of the earth gravity) at a point with a rad

Anna71 [15]

Answer:

$a_{r} = 1006.382g \,\frac{m}{s^{2}}$

Explanation:

Let suppose that centrifuge is rotating at constant angular speed, which means that resultant acceleration is equal to radial acceleration at given radius, whose formula is:

$a_{r} = \omega^{2}\cdot R$

Where:

$\omega$ - Angular speed, measured in radians per second.

$R$ - Radius of rotation, measured in meters.

The angular speed is first determined:

$\omega = \frac{\pi}{30}\cdot \dot n$

Where $\dot n$ is the angular speed, measured in revolutions per minute.

If $\dot n = 3000\,rpm$ , the angular speed measured in radians per second is:

$\omega = \frac{\pi}{30}\cdot (3000\,rpm)$

$\omega \approx 314.159\,\frac{rad}{s}$

Now, if $\omega = 314.159\,\frac{rad}{s}$ and $R = 0.1\,m$ , the resultant acceleration is then:

$a_{r} = \left(314.159\,\frac{rad}{s} \right)^{2}\cdot (0.1\,m)$

$a_{r} = 9869.588\,\frac{m}{s^{2}}$

If gravitational acceleration is equal to 9.807 meters per square second, then the radial acceleration is equivalent to 1006.382 times the gravitational acceleration. That is:

$a_{r} = 1006.382g \,\frac{m}{s^{2}}$

6 0

3 years ago

What is the gravitational force between two 60.0 kg people sitting 100 m<br> apart?

Finger [1]

Answer:

2.4 × 10^(-11) N

Explanation:

F = Gm²/r²

F = 6.67×10^(-11) × 60² / 100²

= 2.4×10^(-11) N

7 0

4 years ago

A convex, or converging, lens with a focal length of 34 cm is used to observe an image of an apple than is 80 cm away from the l

Hatshy [7]

The image distance is 59.2 cm and the image is real and small.

<h3>Image distance</h3>

The distance of the image formed by the convex or converging lens is determined by applying the following lens equation.

1/f = 1/u + 1/v

where;

f is the focal length = 34 cm
u is the object distance = 80 cm
v is the image distance = ?

1/v = 1/f - 1/u

1/v = 1/34 - 1/80

1/v = 0.0294 - 0.0125

1/v = 0.0169

v = 1/0.0169

v = 59.2 cm

Thus, the image distance is 59.2 cm and the image is real and small.

Learn more about convex lens here: brainly.com/question/10153605

8 0

3 years ago