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BlackZzzverrR [31]
3 years ago
10

)) a. Write three side lengths that will

Mathematics
2 answers:
Zolol [24]3 years ago
3 0

Answer:

3,4,5 forms a right triangle

1,2 ,9 does not form a triangle

Step-by-step explanation:

Three side lengths that will form a triangle

3,4,5

This is a Pythagorean triple.  It forms a right triangle

3^2 +4^2 = 5^2

9+16=25

25=25

Three side lengths that will not form a triangle

1,2 9

The sum of the two smaller sides must be greater then the third

1+2 < 9 not greater

Karolina [17]3 years ago
3 0
Three side lengths that will for a. Triangle is 3,4,5 and three side lengths that won’t is 3,4,7
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Step-by-step explanation:

How to find inverse function:

Step 1: Write down equation.

f(x) = 4 \sin(x)  + 3

Remeber Ruler notation that

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Next, we must isolate x so first we subtract 3.

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If you want another proof: Here's one,

Let plug an a x value for the orginal equation,

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x =  \frac{\pi}{2}

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So let see.

\sin {}^{ - 1} ( \frac{7 - 3}{4} )  =  \sin {}^{ - 1} ( \frac{4}{4} )  =  \sin {}^{ - 1} (1)  =  \frac{\pi}{2}

So this is the inverse function of 4 sin x+3.

1b. The range of f(x) is [-1,7).

We can use transformations to describe range.

We have

f(x) = 4 \sin(x)  + 3

Parent function is

\sin(x)

with a range of [-1,1].

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4 \sin(x)

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Then we add a vertical shift of 3.

4 \sin(x)  + 3

So our range of 4 sin x+3.

[-1,7].

1c. Domain of a inverse function is the range of the orginal function.

The range of f(x) is [-1,7) so the domain of f^-1(x) is [-1,7].

f(x) domain was restricted to -pi/2 to pi/2 so the range of f^-1(x) is [-pi/2, pi/2]

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