Which concept can be used to prove that the diagonals of a parallelogram bisect each other?

Mathematics

2 answers:

vlabodo [156]2 years ago

8 0

The answer to this question is A)Congruent Triangles.

Hope I helped you :D

Len [333]2 years ago

5 0

Answer:

Option: A is correct (congruent triangles)

Step-by-step explanation:

To prove that he diagonals of a parallelogram bisect each other we have to go through the following steps:

Angle DBA is congruent to angle BDC.

Angle CMD is congruent to angle AMB.

<em>Triangle CMD is congruent to triangle AMB. </em>

Segment AM is congruent to segment MC.

M is the midpoint of segment AC.

Segment BD bisects segment AC.

Segment BM is congruent to segment MD.

M is the midpoint of segment BD.

Segment AC bisects segment BD.

Hence we have to use the concept of congruent triangles in order to prove that the diagonals of a parallelogram bisect each other.

Hence, option A is correct

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A statue is mounted on top of a 16 foot hill. From the base of the hill to where you are standing is 77 feet and the statue subt

DanielleElmas [232]

Consider right triangle with vertices B - base of the hill, S - top of the statue and Y - you. In this triangle angle B is right and angle Y is 13.2°. If h is a height of the statue, then the legs YB and BS have lengths 77 ft and 16+h ft.

You have lengths of two legs and measure of one acute angle, then you can use tangent to find h:

$\tan 13.2^{\circ}=\dfrac{\text{opposite leg}}{\text{adjacent leg}} =\dfrac{16+h}{77}, \\ \\ 0.2345=\dfrac{16+h}{77},\\ \\ 16+h=0.2345\cdot 77=18.0565,\\ h=18.0565-16=2.0565$ ft.