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Andre45 [30]
3 years ago
9

If f(x) = 3x2 + 1 and g(x) = 1 - X, what is the value of (f – 9)(2)?

Mathematics
2 answers:
bezimeni [28]3 years ago
4 0
The answer is 36 because you have to multiply it and divide getting your the answer.
s344n2d4d5 [400]3 years ago
4 0
The answer to the question is 36
You might be interested in
Let A= {a,b,c,d,e} and let B= {1,2,3,4,5} determine n(AxB)
777dan777 [17]

n(AxB) = 25

Step-by-step explanation:

AxB in sets is called Cartesian product. And is defined as a set of ordered pairs (a,b) where a belongs to A and b belongs to B.

Given

A = {a,b,c,d,e}

B = {1,2,3,4,5}

The number of elements for Cartesian product of two sets is determined by:

n(AxB) = n(A) * n(B)

Here

n(A) = 5\\n(B) = 5

So,

n(AxB) = 5*5 = 25

Hence,

n(AxB) = 25

Keywords: Sets, Cartesian Product

Learn more about sets at:

  • brainly.com/question/5102020
  • brainly.com/question/5147732

#LearnwithBrainly

7 0
3 years ago
Evaluate 1/6 + 2/3 PLEASEEEEEE HELP
mart [117]

2/3 = 4/6.

1/6 + 4/6 = 5/6.

The answer is 5/6.

7 0
3 years ago
Read 2 more answers
2.5 (8.6 ÷ 2 – 1.8)
Alina [70]

Answer:

6.25 is the answer

Step-by-step explanation:

work in the () first

2.5(8.6÷2-1.8)

2.5(2.5)

the multiply the two numbers and get 6.25

hope this helps

7 0
3 years ago
Read 2 more answers
Segments in Circles<br><br><br> TW=3, CW=x, TU=x+7, VW=6. Find the value of x.
Kryger [21]

Answer:

x=2

Step-by-step explanation:

The diagram is attached below

  • TW=3
  • CW=x
  • TU=x+7
  • VW=6

TU=TW+WU

x+7=3+WU

WU=x+7-3

WU=x+4

To determine the value of x, we apply the theorem of intersecting chords.

TW X WU = CW X WV

x(x+4)=6 \times x\\x^2+4x=6x\\x^2=6x-4x\\x^2=2x\\$Divide both sides by x\\x=2

4 0
3 years ago
15, Evaluate 6 choose 4.
Novosadov [1.4K]

Answer:  The required result is 15.

Step-by-step explanation:  We are given to evaluate the following :

"6 choose 4".

Since we are to choose 4 from 6, so we have to use the combination of 6 different things chosen 4 at a time.

We know that

the formula for the combination of n different things chosen r at a time is given by

^nC_r=\dfrac{n!}{r!(n-r)!}.

For the given situation, n = 6  and  r = 4.

Therefore, we get

^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6!}{4!2!}=\dfrac{6\times5\times4!}{4!\times2\times1}=15.

Thus, the required result is 15.

4 0
3 years ago
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