Answer:
7groups
Step-by-step explanation:
15+6/3=7groups
The answer is 
.
Solution:
Use algebraic identity: 
For example: 
Given expression 
and 
.
To multiply these equations.
Combine like terms together.
Hence the answer is .
Moving left subtracts from the x value the number you move.
In (2,9) the x value is the number 2
You move 1 unit to the left so subtract 1 from 2:
2-1 = 1
You will be at (1,9)
<span>The nonpermissible replacement for the variable x in this expression is x = 2
Substituting x = 2 yields:
(2)^2/(2(2)-4)
4/0, which is undefined.
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</span>
Answer:
-1
Step-by-step explanation:
