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Gnom [1K]
2 years ago
6

My teacher can grade 25 homework assignments in 20 minutes. Is she working at a faster rate or slower rate than Ms. Jones, who i

s grading 36 homework assignments in 30 minutes?
Mathematics
1 answer:
Neko [114]2 years ago
7 0

Answer:

Ms.Jones is faster

Step-by-step explanation:

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Referring to the figure, refer to the coordinate system shown and write the ordered pair that names point G. a. (-4, -1) c. (2,
mylen [45]
Answer: c. (2,-1)

Explanation: starting from the origin (0,0), you can see that point G is two places to the right and one down. This indicates that it is (2,-1)
5 0
3 years ago
What is the value of x?
Triss [41]
Sides that two side is equal so
5x+10=40
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5 0
3 years ago
Convert 4x + 2y = 25 from standard form to slope intercept form<br><br> Show your steps
Zigmanuir [339]

Answer:

<em>y = -2x + 25/2</em>

Step-by-step explanation:

Slope intercept form is y = mx + b.

You must solve the equation for y.

4x + 2y = 25

Subtract 4x from both sides.

2y = -4x + 25

y = -2x + 25/2

7 0
3 years ago
Tim needs 3 pounds of vegetables for a vegetable soup recipe.
klio [65]

Answer:

25/12 - pounds more vegetables

Step-by-step explanation:

first we need to put these variables into like terms

36/12 - 3

8/12 - 2/3

3/12 - 1/4

add the last two up and subtract from the first and you get how much you need left over

8 0
3 years ago
Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
3 years ago
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