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3 years ago

Volume measures the amount of ________ a 3D shape can hold

Mathematics

1 answer:

mylen [45]3 years ago

6 0

It is matter

Happy to help!
(Mark brainliest)

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This is hard pls help.

Ksivusya [100]

Answer: 100, LORD OF MERCY, HOW DO YOU NOT KNOW THIS :sob: anyways if you need more help dm me on discord nishimiya#0001

6 0

3 years ago

The square of a non-zero number is equal to 70% of the original number. What

aleksandr82 [10.1K]

Answer:

0.7.

Step-by-step explanation:

x^2 = 0.7x

x^2 - 0.7x = 0

x(x - 0.7) = 0

x = 0, 0.7.

3 0

2 years ago

Ann travels from Town A to Town B in 3 hours. She then takes another hour to travel from Town B to Town C. The distance from Tow

fiasKO [112]

Answer:

35 miles per hour

Step-by-step explanation:

Ann travels a total of (100 +40) = 140 miles in (3 +1) = 4 hours. Her average speed is the ratio of these:

speed = distance/time

speed = (140 miles)/(4 hours) = 35 miles/hour

7 0

3 years ago

If an airplane in a 1 in. : 4 ft. scale drawing is 5 in. long, how long is the actual airplane? Use proportions to solve the pro

Lunna [17]

Answer:

20ft

Step-by-step explanation:

20ft is the answer because you would do 4 x 5 = 20, since the scale factor is 1in : 4ft

Hope this helped :)

4 0

3 years ago

10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the

Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

$H_0: \mu = 0$

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

$H_1: \mu > 0$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

In this problem, the parameters are given as follows:

$\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50$ .

Hence, the test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}$

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by $t^{\ast} = 2.4$ .

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0

2 years ago