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NISA [10]
3 years ago
13

Two students form a group of eight boys and 12 girls are sent to represent the school in a parade. If the two students are chose

n at random, what is the probability that the students chosen are not both girls?
Mathematics
2 answers:
ch4aika [34]3 years ago
6 0
Your best option would be 33/95 hope this helps
irakobra [83]3 years ago
6 0

Answer:  The required probability is 65.26%.

Step-by-step explanation:  Given that two students form a group of eight boys and 12 girls are sent to represent the school in a parade.

We are to find the probability that the students chosen are not both girls, if the two students are chosen at random.

Total number of students in the group = 8 + 12 = 20.

Let S denote the sample space for the experiment of selecting two students and A denote the event that both the students are not girls.

Then,

n(S)\\\\=^{20}C_2\\\\\\=\dfrac{20!}{2!(20-2)!}\\\\\\=\dfrac{20\times19\times18!}{2\times1\times18!}\\\\=190,\\\\\\\\n(A)\\\\\\=^8C_2\times^{12}C_0+^8C_1\times^{12}C_1\\\\\\=\dfrac{8!}{2!(8-2)!}\times1+8\times12\\\\\\=28+96\\\\=124.

Therefore, the probability of event A is given by

P(A)=\dfrac{n(A)}{n(S)}=\dfrac{124}{190}=\dfrac{62}{95}\times100\%=65.26\%.

Thus, the required probability is 65.26%.

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