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lys-0071 [83]
2 years ago
5

If one of the zeroes of the cubic polynomial p(x)=ax³+bx²+cx+d is zero then find the product of other two zeroes of p(x).​

Mathematics
1 answer:
Zigmanuir [339]2 years ago
6 0

Answer:

As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.

Since x is a factor , d= 0

ax^3+bx^2+cx+d = ax^3+bx^2+cx

= x(ax^2+bx+c)

Other two roots are roots of

ax^2+bx+c = 0

For a quadratic equation ax^2+bx+c = 0

Product of roots = c/a

Sum of roots = -b/a

So

Product of other two roots = c/a

Hope this helps :D

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When Cullen cleaned behind his dresser, he found 73 cents, all in nickels and pennies. There were 25 coins. How many were nickel
Georgia [21]
Let n = number of nickels, and p = number of pennies.
The number of coins is 25, so we get this equation.
n + p = 25

The value of the coins is 0.05 per nickel, and 0.01 per penny.
0.05n + 0.01p = 0.73

Now you have a system of equations.

n + p = 25
0.05n + 0.01p = 0.73

Solve the first equation for n:
n = 25 - p

Now substitute into the second equation.

0.05(25 - p) + 0.01p = 0.73

1.25 - 0.05p + 0.01p = 0.73

-0.04p = -0.52

p = 13

There were 13 pennies.
Now we substitute 13 for p in n + p = 25 to find out the number of nickels.

n + 13 = 25
n = 12

There are 13 pennies and 12 nickels.

Check: 13 pennies and 12 nickels does total 25 coins.
13 * 0.01 + 12 * 0.05 = 0.13 + 0.60 = 0.73
The value is $0.73.
Our answer is correct.
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