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lys-0071 [83]
2 years ago
5

If one of the zeroes of the cubic polynomial p(x)=ax³+bx²+cx+d is zero then find the product of other two zeroes of p(x).​

Mathematics
1 answer:
Zigmanuir [339]2 years ago
6 0

Answer:

As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.

Since x is a factor , d= 0

ax^3+bx^2+cx+d = ax^3+bx^2+cx

= x(ax^2+bx+c)

Other two roots are roots of

ax^2+bx+c = 0

For a quadratic equation ax^2+bx+c = 0

Product of roots = c/a

Sum of roots = -b/a

So

Product of other two roots = c/a

Hope this helps :D

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Leo's bank balances at the end of months 1, 2, and 3 are $1500, $1530, and $1560.60,
grandymaker [24]

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Step-by-step explanation:

It is given that the balances follow a geometric sequence

First of all, we have to find the common ratio

Here

a_1 = 1500\\a_2 = 1530\\a_3 = 1560.60

Common ratio is:

r = \frac{a_2}{a_1} = \frac{1530}{1500} = 1.02\\r = \frac{a_3}{a_2} = \frac{1560.60}{1530} = 1.02

So r = 1.02

The general form for geometric sequence is:

a_n = a_1r^{n-1}

Putting the first term and r

a_n = 1500 . (1.02)^{n-1}

To find the 9th month's balance

Putting n=9

a_9 = 1500 . (1.02)^{9-1}\\= 1500.(1.02)^8\\=1757.4890

Rounding off to nearest hundredth

$1757.49

Hence,

Leo's balance after 9 months will be: $1757.49

Keywords: Geometric sequence, balance

Learn more about geometric sequence at:

  • brainly.com/question/10772025
  • brainly.com/question/10879401

#LearnwithBrainly

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3 years ago
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