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Vladimir [108]
4 years ago
15

-49x^2 +16 factor completely

Mathematics
2 answers:
zmey [24]4 years ago
8 0
(-7x+4)(7x+4)
-49x^2-28x+28x+16
rosijanka [135]4 years ago
3 0
Recognize the difference of 2 perfect squares

remember
a²-b²=(a-b)(a+b)
so

we can rearange them to look like this:
16-49x²
then show the squares
(4)²-(7x)²
then factor
(4-7x)(4+7x)
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I need help its my homework and it's due today<br>Find the base angles.​
MrRa [10]

Answer:

Each base angle would be 70°.

Step-by-step explanation:

<em>*</em><em>Base angles means the two equal angles formed on the base are called base angles.</em>

<em> </em><em>B</em><em>ase means the third unequal side of the triangle.</em><em> </em><em>*</em>

Given triangle is isosceles triangle.

The angle of vertex which is given is <u>40°</u>.

Let each base angle be <em>x</em>.

We know that,

<em>There are two base angles in a isosceles triangle</em>.

And, Sum of angles of triangle is 180° .

Therefore,

\tt \implies \: x + x   + 40 {}^{ \circ}  = 180 {}^\circ

Now Solve For <em>x</em>. That would be the solution.

Steps:

<u>Combine like terms:</u>

\tt \implies2x + 40{}^{ \circ}  = 180{}^{ \circ}

<u>Subtract 40 from both sides:</u>

\tt \implies2x + 40{}^{ \circ}  - 40 = 180{}^{ \circ}   - 40{}^{ \circ}

<u>Simplify </u><u>the</u><u> </u><u>LHS </u><u>and </u><u>RHS</u><u>:</u>

\tt \implies2x + 0 = 140{}^{ \circ}

\tt \implies2x = 140 {}^{ \circ}

<u>Divide both sides by 2:</u>

\tt \implies \cfrac{2x}{2}  =  \cfrac{140{}^{ \circ} }{2{}^{ \circ} }

<u>Use cancellation method and cancel LHS and RHS:</u>

\tt \implies  \cfrac{ \cancel2x}{ \cancel2}  =  \cfrac{ \cancel{140^{ \circ}} }{ \cancel{2{}^{ \circ} }}

\tt \implies \cfrac{1x}{1}  =  \cfrac{70{}^{ \circ} }{1{}^{ \circ} }

\tt \implies{1x}  = {70}^{ \circ}

\tt \implies{x} = 70{}^{ \circ}

Hence, each base angle would be 70°.

<u>Verification</u>:

As we know that sum of angles of triangle is 180°.

So,

\tt \implies \: Base \:  angle + other \:  base \:  angle  + vertex \: angle= 180{}^{ \circ}

We got that one base angles of the given isosceles triangle is 70° and other is 70°, and the vertex angle is 40°[Given].

\tt \implies70{}^{ \circ}  + 70{}^{ \circ}  + 40{}^{ \circ}  = 180{}^{ \circ}

<u>Solve it.</u>

\tt \implies140{}^{ \circ}  + 40{}^{ \circ}  = 180{}^{ \circ}

\tt \implies180{}^{ \circ}   = 180{}^{ \circ}

\tt \: LHS  = RHS

\star \sf \: Hence, Verified.

\rule{225pt}{2pt}

I hope this helps!

Let me know if you have any questions.

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