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2 years ago

Find the equation for the line that is parallel to the line with the equation y=4 passing through the point (-4,4).

1 answer:

3 0

The only line that would be parallel to this line and still hit that point would be that line. Is that an option, or did the paper maybe say (4,-4) or maybe even say to draw the line perpendicular to the point?

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Please help due tonight !!!!

gregori [183]

Answer:

okay where is the question

Step-by-step explanation:

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2 years ago

WILL MARK BRAINIEST! 25 points!!! What is the x-coordinate of the solution to the following system of equations? 2x + y = −4 5x

vladimir2022 [97]

Answer:

x=-6

Step-by-step explanation:

2x+y=-4

5x+3y=-6

solve :

multiply first equation by 3

6x+3y=-12

5x+3y=-6

subtract the two equations : 6x+3y-5x-3y=-12-(-6)

x=-12+6

x=-6

6 0

3 years ago

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Natasha_Volkova [10]

Answer:

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2 years ago

How do you find a slope of a line using only two points??

Helen [10]

Its the difference between the y- values divided by the distance between the corresponding x values. Or its sometimes called rise / run.

8 0

3 years ago

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Which equation represents the polar form of x² + (y + 4)² = 16?

Paraphin [41]

$x^2+y^2=r^2\hspace{5em}x=r\cos(\theta )\hspace{5em}y=r\sin(\theta ) \\\\[-0.35em] ~\dotfill\\\\ x^2+(y+4)^2=16\implies x^2+\stackrel{binomial~expansion}{y^2+8y+16}=16 \\\\\\ \underset{x^2+y^2}{r^2} + 8(~\underset{8y}{r\sin(\theta )}~)=16-16\implies r^2+8r\sin(\theta)=0 \\\\\\ r^2=-8r\sin(\theta )\implies \cfrac{r^2}{r}=-8\sin(\theta )\implies r=-8\sin(\theta )$

3 0

1 year ago