Answer:
2. Division property of equality
3. x+1 = -4
4. Subtraction property of equality
5. x = -5
Step-by-step explanation:
Answer:
the correct answer is truly
Step-by-step explanation:
STOP CHEATING ON THID APP
For the derivative tests method, assume that the sphere is centered at the origin, and consider the
circular projection of the sphere onto the xy-plane. An inscribed rectangular box is uniquely determined
1
by the xy-coordinate of its corner in the first octant, so we can compute the z coordinate of this corner
by
x2+y2+z2=r2 =⇒z= r2−(x2+y2).
Then the volume of a box with this coordinate for the corner is given by
V = (2x)(2y)(2z) = 8xy r2 − (x2 + y2),
and we need only maximize this on the domain x2 + y2 ≤ r2. Notice that the volume is zero on the
boundary of this domain, so we need only consider critical points contained inside the domain in order
to carry this optimization out.
For the method of Lagrange multipliers, we optimize V(x,y,z) = 8xyz subject to the constraint
x2 + y2 + z2 = r2<span>. </span>
<h2>Answer:
The line from the question [ y = -8x + 3 ] passes through the point ( -1, 11 ). </h2>
<h3 /><h3>Step-by-step explanation:
</h3>
<u>Find the slope of the parallel line</u>
When two lines are parallel, they have the same slope.
⇒ if the slope of this line = - 8
then the slope of the parallel line (m) = - 8
<u>Determine the equation</u>
We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:
⇒ y - 11 = - 8 (x - (-1))
∴ y - 11 = - 8 (x + 1)
We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:
since y - 11 = - 8 (x + 1)
y = - 8 x + 3
The line from the question [ y = -8x + 3 ] passes through the point ( -1, 11 ).
According to the valence number of copper(2+) and the same value for chlorine (1-) copper (II) chloride has the formula of CuCl2
The molar mass of copper is 0,0635 kg/mole and chlorine gas a molar mass of 0,035 kg/mole the compound will have a molar mass of ( 0,0635+2×0,035 )kg/mole=0,099kg/mole and 0,344 moles are equivalent in mass to 0,344×0,135 kg=0,046 kg
