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3 years ago

13

hich three lengths could be the lengths of the sides of a triangle? A) 11 cm, 11 cm, 24 cm B) 18 cm, 12 cm, 9 cm C) 9 cm, 19 cm,

10 cm D) 4 cm, 7 cm, 23 cm

2 answers:

kondor19780726 [428]3 years ago

7 0

Answer:

B

Step-by-step explanation:

pickupchik [31]3 years ago

6 0

It’s a) because the triangle has 2 equal sides and one not

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What is the distance between A (-4,2) and B (12,4)

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$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
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Use any method to multiply (3a + 2b - c)(a - b + 2c).

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Answer: $3a^{2}-ab + 5ac- 2b^{2} + 5bc-2c^{2}$

Step-by-step explanation:

(3a + 2b − c) (a − b + 2c)

Expand (3a + 2b − c) (a − b + 2c) by multiplying each term in the first expression by each term in the second expression.

3a ⋅ a + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3 (a ⋅ a) + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 + 3 ⋅ −1ab + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 3 ⋅ 2ac + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1b ⋅ b + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1 (b ⋅ b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1b^2 + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 2 ⋅ 2bc − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca − 1 ⋅ −1cb − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + 1cb − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2c ⋅ c

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3a^2 − ab − 2b^2 + 4bc + bc + 5ac − 2c^2

3a^2 − ab − 2b^2 + 5bc + 5ac − 2c^2

3a^2 − ab − 2b^2 + 5ac + 5bc − 2c^2

3a^2 − ab + 5ac − 2b^2 + 5bc − 2c^2

6 0

3 years ago

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blagie [28]

Answer:

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Step-by-step explanation:

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