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iren [92.7K]
3 years ago
5

Jan and Jo live 1,170 miles apart. At the same time, they start driving toward each other on the same road. Jo’s constant rate i

s 60 mph. Jan’s is 70 mph. How long will it take them to meet?
Mathematics
2 answers:
Dafna11 [192]3 years ago
7 0
To get the time taken for Jan and Jo to meet we proceed as follows;
Jan's speed=70 mph
Jo's speed =60 mph
distance between =1170
relative speed=70+60=130
time taken for them to meet will be:
time=(distance)/(relative speed)
=1170/130
=9 hours
the answer is 9 hours
irakobra [83]3 years ago
4 0

Answer:

the answer is 9 hours

Step-by-step explanation:

I got it right on the test

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Tina was asked to determine the possible dimensions of a given rectangle whose area is 12a4b3-18a6b3-72a7b3. Tina stated that th
Rufina [12.5K]

Answer:

Tina is correct

Step-by-step explanation:

Given

Area = 12a^4b^3 - 18a^6b^3 - 72a^7b^3

Required

State if 3a^4b^3(4-6a^2-24a^3) is a possible dimension

To do this, we simply expand 3a^4b^3(4-6a^2-24a^3)

3a^4b^3(4-6a^2-24a^3)

3a^4b^3 * 4-3a^4b^3 * 6a^2-3a^4b^3 * 24a^3

12a^4b^3 - 18a^{4+2}b^3 * -72a^{4+3}b^3

12a^4b^3 - 18a^{6}b^3 * -72a^{7}b^3

By comparison, the result of the expansion

12a^4b^3 - 18a^{6}b^3 * -72a^{7}b^3

and the given expression

Area = 12a^4b^3 - 18a^6b^3 - 72a^7b^3

are the same.

<em>Hence, Tina is correct</em>

7 0
3 years ago
Solve the system using an equivalent system
DerKrebs [107]
Add y to both sides in 1st equation
-2x=y
sub -2x for y in2nd equation
3x-(-2x)=10
3x+2x=10
5x=10
divide 5
x=2

sub back
-2x=y
-2(2)=y
-4=y

(x,y)
(2,-4)
C is ans
8 0
3 years ago
If you run for 0.4 hours at 7 mph, how fast should you walk during the next 0.8 hours to have the average speed of 5 mph?
Orlov [11]

4mph

0.4 x 7 mph =2.8 miles - distance run.

Let the required speed =S

[2.8 + 0.8S] / [0.4+0.8] =5, solve for S

S =4 mph - must walk to attain an average of 5 mph, or:

6 miles / 1.2 hours =5 mph

8 0
4 years ago
Read 2 more answers
-24÷-8-13 Calculate <br>show all your calculations​
I am Lyosha [343]

Answer: -10

Step-by-step explanation:  -24/-8 = 3

3-13 = -10

8 0
3 years ago
Read 2 more answers
What conditions would be enough to prove that P is the circumcenter of HJK ?
BlackZzzverrR [31]

Answer:

Option A and C

Step-by-step explanation:

<u>Explanation for why I choose option A</u> :-

If you look at the triangle, HK has a midpoint of point L, HJ has a midpoint of point M, and KJ has a midpoint of point N. Now if you stretch the lines inside of the triangle, they intersect at point P which is known as the circumcenter of HJK, true.

<u>Explanation</u><u> </u><u>for</u><u> </u><u>why</u><u> </u><u>I</u><u> </u><u>choose</u><u> </u><u>option</u><u> </u><u>C</u> :-

Now let us look at the lines stretch inside of the triangle. There are three lines which are congruent. Those lines are PK, HP, and PJ (they are the big lines inside the triangle) are congruent. Since those three line intersect at point P, it make the statement true that P is the circumcenter of HJK.

  • Why option B is not an answer?

We do not know the third line (PN) measurements to find that if the three lines (PL, PM, and PN) are congruent and equal 90⁰. Since we do not know, it would not prove that they are congruent and P is the circumcenter of HJK.

  • Why option D is not an answer?

Well it says that triangle HJK is an acute triangle which is true, but this doesn't prove that P is the circumcenter of HJK.

I hope this helps, thank you :) !!

4 0
3 years ago
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