To solve this problem, first we have to find the measure of <BAC. To do this, we must set up an equation that represents that <BAC and <DAB are supplementary, meaning their sum is 180 degrees. Since we know that <DAB is 123 degrees, we can make our equation: 180 = 123 + m<BAC. To solve this equation, we simply just subtract 123 from both sides, making your answer: m<BAC = 57 degrees.
Next, we must use our knowledge that the three inner angles of a triangle must add up to a total of 180 degrees. Therefore, 180 = 58 + 57 + x, using our knowledge from previous work and the values from the figure. If we combine like terms on the right side of the equation, we get: 180 = 115 + x. Our final step is to subtract 115 from both sides to get the variable x alone, so we get: x=65.
Therefore, your answer is x=65 degrees.
Hope this helps!
Triangle on the left: 30 60 90 right triangle
so ratio of short leg: long leg: hypo = x : x√3 : 2x
given hypo = 4√3
so
short leg = 4√3 / 2 = 2√3
long leg = 2√3 * √3 = 6
a = 6 and c = 2√3
triangle on the right is 45 45 90 right triangle
so ratio of leg: leg: hypo = x : x : x√2
from above you know a = 6 so d = a = 6
b = 6√2
Answer
a = 6, b = 6√2, c =2√3 and d = 6
I think it's width= 3 times length
So the 1. length is 18/3=6
The 2. Width is 8*3=24
The 4. width is 12*3=36
Answer:
Ok, when we have a point (x, y) and we do a rotation of 90° the new points will actually depend on the quadrant where we are, but it will always change the order to (y, x) but this does not end here, because depending on the quadrant where the point ends, the signs will change as follows.
1st quad (+y, +x)
2nd quad (-y, +x)
3rd quad (-y, -x)
4th quad (+y, -x)
So if we are in the second quadrant, the transformed point will be in the first quadrant
Now, we have that the points G and H are:
G = (-1, 3)
This point is in the second quadrant, so it moves to the first quadrant (where bot values must be positive).
The new point will be:
G´ = (3, 1)
And the other point is:
H = (-4, 0)
It also rotates to the first quadrant, so the new point will be:
H' = (0, 4)