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Svet_ta [14]
3 years ago
12

A car has an initial value of $20,000. The value then "depreciates" or decreases by 10% of its initial value each year. Which eq

uation below gives the value of the car, v, after y years?
A) v= 0.10y+ 2,000
B) v= 0.10y -2,000
C) v=2,000y-20,000
D) v=-2,000y+20,000
Mathematics
1 answer:
Elden [556K]3 years ago
8 0

Answer:

D) v = -2,000y + 20,000.

Step-by-step explanation:

The question gives a linear relationship between two quantities.  This means that the relationship between the initial value of the car and the amount it depreciates each year is proportional, or constant.  Since the value of the car decreases by 10% of its initial value each year, then each year the value will decrease by 10% of 20,000 or 0.10 x 20000 = $2,000.  Since we know the value is decreasing each year, this amount would be subtracted from the initial value of $20,000.  So, D) v = -2,000y + 20,000 would be the only equation that represents this scenario.  

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Step-by-step explanation:

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A: 15 and 21 both have a factor of 3.

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Answer:

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I need help with number 19
inysia [295]
Let's start by understanding that the graph is a linear line. We have a common difference if 4.5 for every 10x we have more.

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4 0
3 years ago
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