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If x=1 and y=5 we get as 4product of 1+5=9
=4+5=9
9=9
lhs=rhs
Answer:
proof below
Step-by-step explanation:
Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)
Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;
(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2
= 2(2a^2 + 2a + 2b^2 + 2b + 1)
Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.
Answer:
Um we can’t see anything it’s just white
Step-by-step explanation:
Answer:
a = 4/27 - b/54
Step-by-step explanation:
27a+1/2b=4
Subtract 1/2 b from each side
27a+1/2b - 1/2 b=4-1/2 b
27a = 4 - 1/2 b
Divide each side by 27
27a/27 = 4/27 - 1/2 b/27
a = 4/27 - b/54