We need to represent the numbers of calls symbolically:
Third evening: x calls
First eve: x-6 calls
Second evening: 3x calls
Find x. Add up these three numbers x, x-6 and 3x and equate your sum to 79:
x+x-6+3x = 79. Then 5x=79+6, or 5x = 85. Thus, x = 17.
17 calls on the 3rd night,
17-6 calls on the 1st night, and
3(17) = 51 calls on the 2nd night.
Check! Add together 17, 11 and 51. Do these add up to 79? Yes.
x² = 8x - 35
x² - 8x + 35 = 0
x = -(-8) ± √(-8)² - 4(1)(35)
2(1)
x = 8 ± √64 - 140
2
x = 8 ± √-76
2
x = -8 ± 4i√19
2
x = -4 ± 2i√19
Answer:
The probability of rolling a sum greater than 1 when rolling two fair numbered cube is 1 or 36/36.
Step-by-step explanation:
There is no 1 as a sum when rolling two fair numbered cubes, so all the sums will be greater than 1.
Step-by-step explanation:
Imagine placing 10 apples in a row.
We have an extra 2 baricades that we can place between any 2 apples, so that a total of 3 groups will be formed.
This is the same as choosing 2 of the 12 items to be barricades.
Hence the answer is 12C2 = 66.
The answer is B. Use distance formula...
