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2 years ago

Need help on question 30 please

Mathematics

1 answer:

padilas [110]2 years ago

3 0

Check the picture below.

make sure your calculator is in Degree mode.

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All the place value of 12,354.897

frutty [35]

All the place values of 12, 354.897 are as follows: 12 thousands, 3 hundred, 5 tens, 4 ones, 0.8 tenths .09 hundredths, .007 thousandths.

4 0

3 years ago

Read 2 more answers

You are offered an item of $17.85 if the sellers states he normally sets the same item for $19.95 what percentage discount it he

nadezda [96]

Answer:

Discount percentage = 10.5% (Approx)

Therefore the discount is seller offering you is 10.5 % .

Step-by-step explanation:

Discount = Marked price - Selling price

As given

You are offered an item for $17.85. If the seller states he normally sells the same item for $19.95 .

Here

Marked price = $19.95

Selling price = $17.85

Discount = 19.95 - 17.85

= $2.1

$\frac{2.1 x 100}{19.95}$

$\frac{210}{19.95}$

Discount percentage = 10.5% (Approx)

Therefore the discount is seller offering you is 10.5 % .

6 0

2 years ago

Find the unknown factor.

pshichka [43]

The answers is -7/6x

3 0

2 years ago

All Seasons Plumbing has two service trucks that frequently need repair. If the probability the first truck is available is 0.75

oksano4ka [1.4K]

Answer: There is a probability of 0.05 that there is neither truck is available.

Step-by-step explanation:

Since we have given that

Probability that the first truck is available = 0.75

Probability that the second truck is available = 0.50

Probability that both trucks are available = 0.30

So, probability that either first truck or second truck is available is given by

$P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\P(A\cup B)=0.75+0.50-0.30\\\\P(A\cup B)=0.95$

We need to find the probability that neither truck is available.

so, P(A∪B)'=1-P(A∪B)

$P(A\cup B)'=1-0.95=0.05$

Hence, there is a probability of 0.05 that there is neither truck is available.

4 0

3 years ago

Solve the equation 5x-2x^2+1

Pani-rosa [81]

Answer:

Step-by-step explanation:

If you call "5x-2x^2+1" an "equation," then you must equate 5x-2x^2+1 to 0:

5x-2x^2+1 = 0

This is a quadratic equation. Rearranging the terms in descending order by powers of x, we get:

-2x^2 + 5x + 1 = 0. Here the coefficients are a = -2, b = 5 and c = 1.

Use the quadratic formula to solve for x:

First find the discriminant, b^2 - 4ac: 25 - 4(-2)(1) = 25 + 8 = 33

Because the discriminant is positive, the roots of this quadratic are real and unequal.

-b ± √(discriminant)

Applying the quadratic formula x = --------------------------------

we get:

-5 ± √33 -5 + √33

x = ----------------- = --------------------- and

2(-2) -4

-5 - √33

---------------

-4

5 0

2 years ago