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3 years ago

how much water could my well hold if the depth of the well is 30ft and the diameter of the well is 24ft

Mathematics

1 answer:

Serga [27]3 years ago

6 0

Answer:

$4,320\pi\ ft^{3}$ or $13,564.8\ ft^{3}$

Step-by-step explanation:

we know that

The volume of the cylinder (well) is equal to

$V=\pi r^{2}h$

we have

$h=30\ ft$

$r=24/2=12\ ft$

substitute

$V=\pi (12)^{2}(30)$

$V=4,320\pi\ ft^{3}$

assume

$\pi=3.14$

substitute

$V=4,320(3.14)=13,564.8\ ft^{3}$

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Using the numbers -4, 10, 8, 2, -3, -5, write down two expressions that equal 6. You can use any relevant operation. You have to

Valentin [98]

Answer:

$\sf \Bigg[ \frac{ ( - 4 \times ( - 3)) }{2} \Bigg] \: and \: \Bigg[ \frac{ - ( - 5 \times 8)}{10} + 2 \Bigg]$

Step-by-step explanation:

Given:

$The \: numbers \rightarrow -4, 10, 8, 2, -3, -5$

To find:

Two expressions that equal 6 using the given numbers

Solution:

Expression first,

Using numbers -4, 2, -3,

aligning the above numbers as,

$\frac{ ( - 4 \times ( - 3)) }{2}$

will out put 6.

Verification,

$\frac{ ( - 4 \times ( - 3)) }{2} = \frac{12}{2} = \cancel\frac{12}{2} = 6$

Expression second,

Using numbers 10,8,2,-5

aligning the above numbers as,

$\frac{ - ( - 5 \times 8)}{10} + 2$

will result 6.

Verification

$\frac{ - ( - 5 \times 8)}{10} + 2 = \frac{ 40}{10} + 2 \\ \\ \frac{ - ( - 5 \times 8)}{10} + 2= 4 + 2 \\ \\\frac{ - ( - 5 \times 8)}{10} + 2 = 6$

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2 years ago

X²-6x Whats the answer?

kow [346]

Answer: x(x−6)

Step-by-step explanation:

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2 years ago

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Find the area of a circle with the diameter of 3 centimeters. Use 3.14 for pi ().

wlad13 [49]

Answer:

7.065 sq. cm

Step-by-step explanation:

Diameter= 3 cm

Since 2r=d, the radius is 1.5 cm

Circle area formula:

πr^2 --> 3.14(r^2)

Plug in r:

A=3.14(1.5^2)

A=3.14(2.25)

A=7.065

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2 years ago

Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 1

sattari [20]

We have that

N 1)
a² − 9a + 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 9a)=-14

Complete the square Remember to balance the equation by adding the same constants to each side

(a² − 9a+20.25)=-14+20.25

Rewrite as perfect squares

(a-4.5)²=6.25--------> (a-4.5)=(+/-)√6.25

a1=4.5+√6.25-----> a1=7

a2=4.5-√6.25-----> a2=2

the solution problem N 1 is the pair {7, 2}

N 2)

a² + 9a + 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square Remember to balance the equation by adding the same constants to each side

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25

a1=-4.5+√6.25-----> a1=-2

a2=-4.5-√6.25-----> a2=-7

the solution problem N 2 is the pair {-2,-7}

N 3)

a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 3a)=10

Complete the square Remember to balance the equation by adding the same constants to each side

(a² + 3a+2.25)=10+2.25

Rewrite as perfect squares

(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25

a1=-1.5+√12.25-----> a1=2

a2=-1.5-√12.25-----> a2=-5

the solution problem N 3 is the pair {2, -5}

N 4)

a² + 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

Complete the square Remember to balance the equation by adding the same constants to each side

(a² + 5a+6.25) =14+6.25

Rewrite as perfect squares

(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25

a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}

N 5)

a² − 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 5a)=14

Complete the square Remember to balance the equation by adding the same constants to each side

(a² − 5a+6.25)=14+6.25

Rewrite as perfect squares

(a-2.5)²=2025--------> (a-2.5)=(+/-)√20.25

a1=2.5+√20.25-----> a1=7

a2=2.5-√20.25-----> a2=-2

the solution problem N 5 is the pair {7, -2}

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3 years ago

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Which expression is equivalent to sqrt2/^3sqrt2

zimovet [89]

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This can be simplified using the radical properties as below

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Now using exponent properties we can write

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3 years ago

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