Answer:-46
Step-by-step explanation: just took test
The zeros of this functions are -4, 2, -4, and -4.
-4 is a multiple zero and has multiplicity 3.
2 is a zero. I would call it a simple zero, since it's only a zero once (AKA has multiplicity of 1).
Is this a "pick one answer" or "pick all correct answers"?
There are 3 numbers as such.
First lets list all the factors of 12
1,2,3,4,6,12
now lets see which are multiples of 3
3,6 and 12 are multiples of 3
therefore we are left with
1,2 and 4
Sin (37°) = opposite side/Hypotenuse
sin (37°) =CV/55 →CV = 55.si (37°)
CV = 55 x (0.601815)
CV= 33
Answer:
The factors are (5x + 3) and (2x + 1)
Step-by-step explanation:
When you need to factor a quadratic, and the coefficient of the x² is not 1, use the slide and divide method.
The general form of a quadratic is ax² + bx + c
Factor: 10x² + 11x + 3
Here a = 10, b = 11, and c = 3
Step 1: Multiply ac, we SLIDE a over to c. Notice the 10 is gone for now..
x² + 11x + 30
Step 2: Factor this (this step will always factor)
x² + 11x + 30 = (x + 5)(x + 6)
So the factors are (x + 5)(x + 6), but we now need to DIVIDE by a, since we multiplied it into c before. We divide the constants in the factors...
(x + 5/10 )(x + 6/10 )
Now reduce the fractions as much as possible...
(x + 1/2 )(x + 3/5)
*If they don't reduce to a whole number, SLIDE the denominator over as a coefficient of x....
(2x + 1)(5x + 3) *2 slide over in front of x, 5 slide over in front of x, the fractions are gone!
These are our factors!
