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3 years ago

Two parallel lines are crossed by a transversal. What is the value of x?

Mathematics

2 answers:

Bond [772]3 years ago

4 0

Answer:

what are the questions

Step-by-step explanation:

marishachu [46]3 years ago

4 0

Is there a picture you can show us ?

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A shop has this offer.

Dima020 [189]

Tim buys 3 shirts for £49 each which is £147 without the discount with the discount it is £137
Craig buys 5 shirts for £49 each which is £245 without the discount with the discount it is £225
so craig spent 225-137=88

ANSWER: £88

6 0

2 years ago

Hitman42 [59]

Answer:

answer of this question is = m⁹n⁶p¹⁵

and plz mark my answer as brainlist if it help you out with this question and plz vote me .....

8 0

3 years ago

PLEASE HELP<br> 2!/0!=<br> 0<br> 2<br> undefined

GuDViN [60]

Answer:

Step-by-step explanation:

any expression divided by 1 remains the same

you can also calculate the factorial

6 0

3 years ago

How can i identify a slope

Nonamiya [84]

Answer:

Rise over Run.

Step-by-step explanation:

If it's on a line on a graph you count how many it goes up until it's aligned with the next point and then you count how ever many over until it hits it. So it could be 2 up and 4 over making the slope 2/4.

I'm sorry that might not make much sense I'm bad at explaining but let me know if that helps at all!!

3 0

3 years ago

Read 2 more answers

You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte

Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

$f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \, otherwise }} \right.$

a) We calculate the probability that you need less than 5 minutes to get up:

$P(x$

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate the probability that you will need between 8 and 13 minutes:

$P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3$

Therefore, the probability is P(8<x<13)=0.3.

d) We calculate the probability that you will be late to each of the 9:30am classes next week:

$P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6$

You have 9:30am classes three times a week. So, we get:

$P=0.6^3=0.216$

Therefore, the probability is P=0.216.

e) We calculate the probability that you are late to at least one 9am class next week:

$P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1$

Therefore, the probability is P=1.

3 0

3 years ago