Using the chain rule.
<span><span>sin^3</span>(x) = [sin(x)<span>]^3
</span></span><span><span>d/<span>dx</span></span>[sin(x)<span>]^3</span>∗<span>d/<span>dx</span></span>[sin(x)]
</span>d/dx sinx = cosx
d/dx<span> cosx = -sinx </span>
d/dx<span> (-sinx) = -cosx </span>
d/dx <span>(-cosx) = sinx
back to where we started from!!! </span>
So,
repeat repeat repeat !!
<h3>
♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>
➷ Pythagoras' theorem:
a^2 + b^2 = c^2
'c' is the hypotenuse and also the longest length
Taking this into consideration, the correct option would be:
C) 11^2 + 60^2 = 61^2
<h3><u>
✽</u></h3>
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
Answer:
463833
expand
Medium
Solution
verified
Verified by Toppr
In △ABD and △ACD, we have
DB=DC ∣ Given
∠ADB=∠ADC ∣ since AD⊥BC
AD=AD ∣ Common
∴ by SAS criterion of congruence, we have.
△ABD≅△ACD
⇒AB=AC ∣ Since corresponding parts of congruent triangles are equal
Hence, △ ABC is isosceles.
Not sure about this but, is it a line?
