All categories

3 years ago

Can someone help with these questions?

Physics

1 answer:

yanalaym [24]3 years ago

6 0

One

Givens

v = 8.5 km/s = 8500 m/s
R = 25 cm = 0.25 m
B = 5.29 * 10^-3
q = 1.6*10^-19
m = ??

Formula

m*v^2/ R = qvB Cancel 1 v on each side.

m*v / R = q*B

which for m when transposed is

m = q*B*R/v

m = 1.6*10^-19 * 5.29*10^-3 * 0.25 / 8500

m = 2.49 * 10^-26

Answer: A

Two

Givens

B = 0.5 T
q = 1.6 * 10^ -19
v = ??
m = 3.34 * 10^-27
R = 55.6 cm = 0.556 m

Formula

qvB = mv^2/R Cancel one of the "v"s

qB = mv/R

qBR / m = v

Solution

1.6*10^-19 * 0.5 T * 0.556 m / 3.34 * 10^-27

13317365 = v

1.33 * 10^7 = v

You might be interested in

The average Intensity of the electromagnetic field due to sunlight at the surface of the earth is 1400 W/m^2. Calculate the maxi

Ann [662]

Answer:

1027 N/C

3.42 x 10⁻⁶ T

Explanation:

I = Intensity of electromagnetic field = 1400 W/m²

E₀ = Maximum value of electric field

Intensity of electromagnetic field is given as

I = (0.5) ε₀ E₀² c

1400 = (0.5) (8.85 x 10⁻¹²) (3 x 10⁸) E₀²

E₀ = 1027 N/C

B₀ = maximum value of magnetic field

using the equation

E₀ = B₀ c

1027 = B₀ (3 x 10⁸)

B₀ = 3.42 x 10⁻⁶ T

4 0

3 years ago

A magnetically soft material is placed in a strong magnetic feild. what is the most likely outcome?

myrzilka [38]

So we want to know what will happen if we put a magnetically soft material in a strong magnetic field. A magnetically soft material is a material whose magnetic field can easily be reversed. Those are ferromagnetic materials. Iron is such a material. When a magnetically soft material is placed into a strong magnetic field it gets its own magnetic field. But its not a permanent magnetic field, it can be changed by a different strong magnetic field.

5 0

3 years ago

All but one statement applies to electromagnetic radiation

lina2011 [118]

<span>D) Electromagnetic radiation travels in the form of longitudinal waves.</span>

3 0

3 years ago

The alternative to nuclear fission reactors in a nuclear fusion reactor. Explain why it is much more difficult to get a fusion r

Sliva [168]

Answer: The major challenges are as

1) understanding of the plasma: Plasma is a soup like mixture of subatomic particles of different atoms nuclei and electrons that are shattered apart by the temperature at which plasma is formed. further research is needed to understand the behavior of plasma so that it can be put to a proper use.

2) Confinement of plasma: Once we get the plasma we need to hold it so that we can obtain heat from it to drive a steam turbine but the sheer temperature of plasma is in millions of Celsius thus currently making it impossible to confine conventionally. Scientists use a loop of electric and magnetic fields to keep it in circulatory like manner so that it can be studied.

3) finally to obtain electricity from the plasma it should be stable to produce electricity. But currently to obtain pressure, temperature so that we have a sustained supply is highly difficult in technical and economical aspects.

Inertial confinement: In order to get the nuclei of atoms close enough for fusion this type of method used compression of the nuclei into highly small volumes.This is accomplished by use of lasers which are directed towards the fuel pellets that implode and travel towards other nuclei making fusion possible. It's main advantage is that it requires lesser time to initiate fusion but the disadvantage being that a large power is used to fire the lasers and the lasers should all hit the small target.

Magnetic Confinement: In this method we use a magnetic and electric fields in a properly designed space to keep the plasma in motion. In motion the nuclei of the atoms come close enough to initiate fusion.It's advantage being less power is required to start the process as compared to inertial confinement and the disadvantage being that plasma confinement is currently not properly understood.

5 0

3 years ago

A uniform, 4.5 kg, square, solid wooden gate 2.0 mm on each side hangs vertically from a frictionless pivot at the center of its

True [87]

Answer:

The angular velocity is $w = 1.43\ rad/sec$