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Inessa [10]
3 years ago
10

Now consider the case in which the object is between the lens and the focal point. Trace the P ray (use the label P1P1P_1 for th

e segment of the P ray on the same side as the object and P2P2P_2 for the segment on the opposite side) and the M ray. Draw the vectors for the incident rays starting from the tip of the object. The location and orientation of the vectors will be graded.

Physics
1 answer:
luda_lava [24]3 years ago
5 0

Answer:

 1 / f = 1 / p + 1 / q

Explanation:

For this exercise we will use two methods, an analytical method which is to use the constructor equation

                 1 / f = 1 / p + 1 / q

where f is the focal length, positive for converging lenses and negative for diverging lenses, p and q are the distance to the object and the image respectively

                 m = h’/ h = - q / p

where m is the magnification, h ’and h are the height of the image and the object.

We will also use a graphical method, where three rays will be traded

1) A ray that passes through the center of the lens and should not

2) a ray that passes through the focal length and comes out parallel to the lens

3) A ray that is horizontal and comes out through the focal from the other side

for this second method see the attachment

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Scrat [10]

Answer:

{ \boxed{ \bold{ \sf{Acceleration \: ( \: a) = 8 \: m/ {s \: }^{2} }}}}

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♨ Question :

  • A car starts from rest and is moving at 60.0 m/s after 7.50 s. What is the car's average acceleration ?

♨ \underbrace{ \sf{Required \: Answer : }}

☄ Given :

  • Initial velocity ( u ) = 0
  • Final velocity ( v ) = 60.0 m/s
  • Time ( t ) = 7.50 s

☄ To find :

  • Acceleration ( a )

✒ We know ,

\boxed{ \underline{ \bold{ \sf{Acceleration \: ( \: a) =  \frac{Final velocity ( v )  - Initial velocity ( u)}{t} }}}}

Substitute the values and solve for a.

➛ \sf{a =  \frac{60.0 - 0}{7.50}}

➛ \sf{a =  \frac{60.0}{7.50}}

➛ \boxed{ \boxed{ \sf{a = 8 \: m/ {s \: }^{2} }}}

---------------------------------------------------------------

✑ Additional Info :

  • When a certain object comes in motion from rest , in the case , initial velocity ( u ) = 0
  • When a moving object comes in rest , in the case , final velocity ( v ) = 0
  • If the object is moving with uniform velocity , in the case , u = v.
  • If any object is thrown vertically upwards in the case , a = -g
  • When an object is falling from certain height , in the case , final velocity at maximum height ( v ) = 0.

Hope I helped!

Have a wonderful time ツ

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