The effiency of a machine is
(output work or energy) / (input work or energy) .
For the system described in the question, that's
(123 J) / (150 J) = 0.82 = 82% .
The term used is " WORK".
I'm really sorry it's not one of the choices.
Answer:
A goal keepee catering the ball in time is answer
No,because they may have more particles
Most as long the hypothesis is a good answer and can be answered
