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fenix001 [56]
2 years ago
8

Which is an example of current electricity? ​

Physics
1 answer:
VARVARA [1.3K]2 years ago
5 0
A. A child rubs a balloon
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the ocean floor is, on average, 4267 m below sea level. What is the pressure in the atmosphere at this depth?
hichkok12 [17]
The pressure at the depth h in the ocean is given by (Stevin's law)
p= p_0 + \rho g h
where
p_0 = 1.0 \cdot 10^5 Pa is the atmospheric pressure
and \rho g h is the pressure exerted by the column of water of height h=4267 m, with \rho = 1000 kg/m^3 being the water density and g=9.81 m/s^2.
Substituting, we find
p=1.0 \cdot 10^5 Pa + (1000 kg/m^3)(9.81 m/s^2)(4267 m)=4.20 \cdot 10^7 Pa
We want to convert this into atmospheres: we know that 1 atm corresponds to the atmospheric pressure at sea level, so 1 atm=1.0\cdot 10^5 Pa, therefore we just need to divide by this number:
p= \frac{4.20 \cdot 10^7 Pa}{1.0 \cdot 10^5 Pa/atm} =420 atm
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It is changing the molecular structure of a protein

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3 years ago
If the angular frequency of the motion of a simple harmonic oscillator is doubled, by what factor does the maximum acceleration
Nataly_w [17]

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When we double the angular velocity the maximum acceleration (a_{max}) will changes by a factor of 4.

Explanation:

Given the angular frequency (\omega) of the simple harmonic oscillator is doubled.

We need to find the change in the maximum acceleration of the oscillator.

a_{max}=A\omega^2

Now, according to the problem, the angular frequency (\omega) got doubled.

Let us plug \omega=2\times \omega. Then the maximum acceleration will be a_{max'}

a_{max}=A\omega^2

a_{max'}=A(2\times \omega)^2\\a_{max'}=A\times 4\omega\\a_{max'}=4A\omega

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We can see, when we double the angular velocity the maximum acceleration will changes by a factor of 4.

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