3 years ago

A car in front of the school goes from rest to 5.6 m/s in 3 seconds. What is its acceleration?

Physics

1 answer:

Nostrana [21]3 years ago

4 0

I’m so so so so sorry I don’t know

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Derive an expression for the gravitational potential energy U(r) of the object-earth system as a function of the object's distan

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Answer:

$U(r)=-\frac{Gm_Emr^2}{2R^3_E}$

Explanation:

We are given that

Gravitational force= $F_g=\frac{Gm_Emr}{R^3_E}$

r=0,U(0)=0

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Gravitational potential energy= $-\int F_gdr$

$U(r)=-\int\frac{Gm_Emr}{R^3_E}dr$

$U(r)=-\frac{Gm_Em}{R^3_E}\times \frac{r^2}{2}+C$

Substitute r=0 ,U(0)=0

$0=0+C$

$C=0$

Substitute the value

$U(r)=-\frac{Gm_Emr^2}{2R^3_E}$

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3 years ago

The current in a resistor is 3.0 A, and its power is 60 W. What is the voltage?

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Answer:

20 volts

Explanation:

Use the equation $P=VI$

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2 years ago

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