Ask question

Ask question

All categories

3 years ago

15

Estimate the sum. Round each number to the nearest whole number, then add. 9 1/2 + 7 1/8

1 answer:

borishaifa [10]3 years ago

4 0

Answer:

12 1/8

Step-by-step explanation:

You might be interested in

Question Progress

rodikova [14]

Answer:

X = 6

Step-by-step explanation:

17 - 5 = 12

12/2 = 6

hope this helps...

8 0

3 years ago

Read 2 more answers

Simplify -8(4-3x)-17x

Luda [366]

1. distribute the -8 into the parentheses and you get -32+24x-17x
2. combine like terms and get -32+7x
3. if you need to make it simpler set the equation = to zero -32+7x=0 and then add the 32 on both sides
4. 7x=32 and then divide by 7 and you get 32/7 or approximately 4.571

I hope this helped!! :)

4 0

3 years ago

Read 2 more answers

Let p: x < −3

myrzilka [38]

Answer:it is the number above the 5

Step-by-step explanation:

5 0

3 years ago

find the zeros of following quadratic polynomial and verify the relationship between the zeros and the coefficient of the polyno

Cloud [144]

Answer:

$\textsf{Zeros}: \quad x=\dfrac {\sqrt{3}}{2}, \:\:x=-\dfrac {4\sqrt{3}}{3}$

Step-by-step explanation:

Rewrite the given polynomial in the form ax² + bx + c:

$f(x)=2 \sqrt{3}x^2+5x-4 \sqrt{3}$

To find the zeros, set the function to zero and solve for x using the quadratic formula.

$\implies 2 \sqrt{3}x^2+5x-4 \sqrt{3}=0$

<u>Quadratic formula</u>:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore,

a = 2√3
b = 5
c = - 4√3

Substituting the values into the quadratic formula:

$\implies x=\dfrac{-5 \pm \sqrt{5^2-4(2\sqrt{3})(-4\sqrt{3})} }{2(2\sqrt{3})}$

$\implies x=\dfrac {-5 \pm \sqrt {121}}{4\sqrt{3}}$

$\implies x=\dfrac {-5 \pm 11}{4\sqrt{3}}$

$\implies x=\dfrac {6}{4\sqrt{3}}, \:\:x=\dfrac {-16}{4\sqrt{3}}$

$\implies x=\dfrac {3}{2\sqrt{3}}, \:\:x=-\dfrac {4}{\sqrt{3}}$

$\implies x=\dfrac {\sqrt{3}}{2}, \:\:x=-\dfrac {4\sqrt{3}}{3}$

The sum of the roots of a polynomial is -b/a:

$\implies -\dfrac{b}{a}=-\dfrac{5}{2 \sqrt{3}}=-\dfrac{5\sqrt{3}}{6}$

The sum of the found roots is:

$\implies \left(\dfrac {\sqrt{3}}{2}\right)+\left(-\dfrac {4\sqrt{3}}{3}\right)=-\dfrac{5\sqrt{3}}{6}$

Hence proving the sum of the roots is -b/a

The product of the roots of a polynomial is: c/a

$\implies \dfrac{c}{a}=\dfrac{-4\sqrt{3}}{2\sqrt{3}}=-2$

The product of the found roots is:

$\implies \left(\dfrac {\sqrt{3}}{2}\right)\left(-\dfrac {4\sqrt{3}}{3}\right)=-\dfrac{12}{6}=-2$

Hence proving the product of the roots is c/a

Therefore, the relationship between the roots and the coefficients is verified.

8 0

2 years ago

A student determined that the area of the segment of OC shown above is A segment = 137.71ft

oksian1 [2.3K]

It would be C because it is right

8 0

3 years ago