Cystic fibrosis is inherited in an autosomal recessive form, meaning that a person has to inherit two abnormal genes for the disease to manifest. In the case of this question, one parent is a gene carrier, so his genotype is Aa, while the other does not have the cystic fibrosis gene, so AA.

Performing the cross of Aa x AA, we can see that:

a.) The probability of a child would have cystic fibrosis is 0%, since the disease is recessive and to be affected it should receive a recessive gene from each parent.

b.) The probability of a child would be a carrier is 50%, as 50% of the crossing phenotypes are Aa.

c.) The probability of a child would not have cystic fibrosis and is not a carrier is 50%, as 50% of the child's genotype is AA.

d.) The probability of a child would be healthy is 100%, as of all possible phenotypes none is affected.

5 0

3 years ago

The perimeter cf a rectangle i: 56 inches" the ratio of the length of the width is 6 : 1. Find the length and the width.

sergejj [24]

Answer: Length = 24; width =4

Step-by-step explanation

Since the ratio of the length to width is 6:1

Let the length be represented as 6x

And the width be = x

Such that that the Perimeter of the rectangle which is

Perimeter = 2(length + width) becomes

56 = 2(6x + x)

56/2 = 6x+x

28 = 7x

x = 4

Width = 4

Length = 6x= 6 x 4 = 24

8 0

2 years ago