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ExtremeBDS [4]
3 years ago
11

Find the values of x and y that satisfies the equation. 5x + 3i = 15 + yi

Mathematics
2 answers:
nexus9112 [7]3 years ago
8 0

Answer:  The required value of x is 3 and that of y is 3.

Step-by-step explanation:  We are given to find the values of x and y that satisfies the following equation :

5x+3i=15+yi~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We know that

a+bi=c+di~~~~~~~~~\Rightarrow a=c,~b=d.

That is, the real and parts on both sides of the equation are equal.

From equation (i), we have

5x+3i=15+yi.

Equating the real and imaginary parts on both sides of the above equation, we get

5x=15\\\\\Rightarrow x=\dfrac{15}{5}\\\\\Rightarrow x=3

and

3=y\\\\\Rightarrow y=3.

Thus, the required value of x is 3 and that of y is 3.

Anestetic [448]3 years ago
6 0

Answer:

So the value of x=3  and y =3

Step-by-step explanation:

5x + 3i = 15 + yi

To find out x   , set the constant terms  equal to each other and solve for x

5x= 15

Divide by 5 on both sides

x= 3

To find out y   , set the ';i' terms  equal to each other and solve for y

3= y

So the value of x=3  and y =3

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Choice D

Step-by-step explanation:

For this one I would find if the point lands on the line.

<em><u>Choice A:</u></em>

What we have to do is to plug in -4 for x and 4 for y.

y=2x+10\\(4)=2(-4)+10\\4=-8+10\\4\ne2

The point is not on this line so this cannot be it.

<em><u>Choice B:</u></em>

We pug what we know again.

y=\frac{1}{3}x+1\\(4)=\frac{1}{3}(-4)+1\\(4)=-\frac{4}{3}+1\\4\ne-\frac{1}{3}

The point is not on this line so it can't be it.

<em><u>Choice C:</u></em>

We pug in what we know again.

y=3x-9\\(4)=3(-4)-9\\(4)=-12-9\\4\ne-21

The point is not on this line so it can't be it.

The next one has to be it, but we'll check it just in case.

<em><u>Choice D:</u></em>

We plug in what we know again.

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