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ExtremeBDS [4]
3 years ago
11

Find the values of x and y that satisfies the equation. 5x + 3i = 15 + yi

Mathematics
2 answers:
nexus9112 [7]3 years ago
8 0

Answer:  The required value of x is 3 and that of y is 3.

Step-by-step explanation:  We are given to find the values of x and y that satisfies the following equation :

5x+3i=15+yi~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We know that

a+bi=c+di~~~~~~~~~\Rightarrow a=c,~b=d.

That is, the real and parts on both sides of the equation are equal.

From equation (i), we have

5x+3i=15+yi.

Equating the real and imaginary parts on both sides of the above equation, we get

5x=15\\\\\Rightarrow x=\dfrac{15}{5}\\\\\Rightarrow x=3

and

3=y\\\\\Rightarrow y=3.

Thus, the required value of x is 3 and that of y is 3.

Anestetic [448]3 years ago
6 0

Answer:

So the value of x=3  and y =3

Step-by-step explanation:

5x + 3i = 15 + yi

To find out x   , set the constant terms  equal to each other and solve for x

5x= 15

Divide by 5 on both sides

x= 3

To find out y   , set the ';i' terms  equal to each other and solve for y

3= y

So the value of x=3  and y =3

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3 years ago
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Scateboard cost Rs450each in my local store,The shop keeper says if I buy 1 I can buyanother for only 7/9 of the normal price,ho
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Answer:

the cost will be Rs 350

Step-by-step explanation:

The Scateboard cost Rs 450 each in the local store,The shop keeper says if I buy 1 I can buy another for only \frac{7}{9} of the normal price. We are asked to determine the cost of a second scateboard .

Hence the cost will be \frac{7}{9} of the normal cost that is

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3 years ago
Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar
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Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 18 means that N = 18

9 are carrying nuclear weapons, which means that k = 9

9 are destroyed, which means that n = 9

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021

P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

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3 years ago
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Maksim231197 [3]

Answer:

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Step-by-step explanation:

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